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Rashid [163]
2 years ago
10

Find the area of a regular polygon

Mathematics
1 answer:
Dimas [21]2 years ago
4 0

Answer:

(N-2)x180=sum of interior angles

So (5-2)x180=540

Divided by number of sides=540/4=108... then each angle is 108 divide to triangles ..so they will have 2 angles =54 2 sides =4 the last angle =72 ."of the triangle " area of triangle =1/2xsxsxsin(side in

between)

So 1/2x4x4xsin(72)= then multiply it by 5 as u will have 5 triangles .. so it will be 190.2(probably i tried)

Step-by-step explanation:

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Answer:

Math properties the programmer had put into the software. The majority of programming software is based in math.

Step-by-step explanation:

The other 3 possible answers make no sense.

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2 years ago
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Match each pair of points to the equation of the line that is parallel to the line passing through the points.
Paraphin [41]

we know that

If two lines are parallel, then, their slopes are equal.

The formula to calculate the slope between two points is equal to


m=\frac{y2-y1}{x2-x1}


we will proceed to calculate the slope in each case, to determine the solution of the problem

<u>Case A)</u> Point B(5,2)\ C(7,-5)

Find the slope BC

Substitute the values in the formula

m=\frac{-5-2}{7-5}


m=\frac{-7}{2}


m=-3.5


so

The equation y=-3.5x-15 is parallel to the line passing through the points B(5,2)\ C(7,-5)

therefore

<u>the answer Part A) is</u>

B(5,2)\ C(7,-5) ------> y=-3.5x-15

<u>Case B)</u> Point D(11,6)\ E(5,9)

Find the slope DE

Substitute the values in the formula

m=\frac{9-6}{5-11}


m=\frac{3}{-6}


m=-0.5


so

The equation y=-0.5x-3 is parallel to the line passing through the points D(11,6)\ E(5,9)

therefore

<u>the answer Part B) is</u>

D(11,6)\ E(5,9) ------> y=-0.5x-3

<u>Case C)</u> Point F(-7,12)\ G(3,-8)

Find the slope FG

Substitute the values in the formula

m=\frac{-8-12}{3+7}  

m=\frac{-20}{10}


m=-2


so

Any linear equation with slope m=-2 will be parallel to the line passing through the points F(-7,12)\ G(3,-8)

<u>Case D)</u> Point H(4,4)\ I(8,9)

Find the slope HI

Substitute the values in the formula

m=\frac{9-4}{8-4}


m=\frac{5}{4}


m=1.25


so

The equation y=1.25x+4 is parallel to the line passing through the points H(4,4)\ I(8,9)

therefore

<u>the answer Part D) is</u>

H(4,4)\ I(8,9) ------> y=1.25x+4

<u>Case E)</u> Point J(7,2)\ K(-9,8)

Find the slope JK

Substitute the values in the formula

m=\frac{8-2}{-9-7}


m=\frac{6}{-16}


m=-0.375


so

Any linear equation with slope m=-0.375 will be parallel to the line passing through the points  J(7,2)\ K(-9,8)

<u>Case F)</u> Point L(5,-7)\ M(4,-12)

Find the slope LM

Substitute the values in the formula

m=\frac{-12+7}{4-5}


m=\frac{-5}{-1}


m=5


so

The equation y=5x+19 is parallel to the line passing through the points L(5,-7)\ M(4,-12)

therefore

<u>the answer Part F) is</u>

L(5,-7)\ M(4,-12) ------>  y=5x+19




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1 year ago
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Answer:

Step-by-step explanation:

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Verdich [7]
Let distance covered by Meng be 'x' (given)

x+3.25=7

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