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Irina-Kira [14]

2 years ago

5

Janice and her dad are building a treehouse. Her dad bought a box of 155 nails for $3.10 and a box of 85 screws for $7.65. How m

uch more do screws cost per piece?

2 answers:

olga2289 [7]2 years ago

8 0

.07 cents more for screws

Degger [83]2 years ago

7 0

3.10/155= 0.02 } subtract = 0.07 more
7.65/85= 0.09 }

You might be interested in

In college basketball, some teams get most of their points from just one player, and other teams are more balanced in scoring. C

lutik1710 [3]

Answer:

(B) At Maryland, the mean number of points per player per game is greater than the median number of points per player per game.

(D)The mean number of points per player per game is the same at all 3 schools.

Step-by-step explanation:

<u>Baylor University</u>

6 players who each score 12 points per game

6 players who each score 0 points per game.

The Scores are: 0,0,0,0,0,0,12,12,12,12,12,12

$Mean=\frac{0+0+0+0+0+0+12+12+12+12+12+12}{12} \\Mean=6\\Median=\frac{12+0}{2}=6$

<u>University of Maryland</u>

1 player scores 58 points per game,

1 player scores 14 points per game,

The rest(10) of the players score 0 points per game.

The Scores are: 0,0,0,0,0,0,0,0,0,0,14,58

$Mean=\frac{0+0+0+0+0+0+0+0+0+0+14+58}{12} \\Mean=6\\Median=\frac{0+0}{2}=0$

<u> Dartmouth College</u>

4 players score 5 points per game,

4 players score 6 points per game,

4 players score 7 points per game.

The Scores are: 5,5,5,5,6,6,6,6,7,7,7,7

$Mean=\frac{5+5+5+5+6+6+6+6+7+7+7+7}{12} \\Mean=6\\Median=\frac{6+6}{2}=6$

The following applies:

(B) At Maryland, the mean number of points per player per game is greater than the median number of points per player per game.

(D)The mean number of points per player per game is the same at all 3 schools.

7 0

1 year ago

Sue played four games of golf for these games her modal score was 98 and her mean score was 100 her range of score was 10 what w

earnstyle [38]

Answer : Remaining two observation becomes 97 and 107.

Explanation :

Since we have given that

Mean = 100

Modal value = 98

Range = 10

As we know that ,

Range = Highest-Lowest

Let highest observation be x

Let lowest observation be y

So equation becomes x-y=10 ----equation 1

So, observation becomes

x,98,98,y

Now, we use the formula of mean i.e.

Mean = $\frac{\text{Sum of observation}}{\text{N.of observaton}}$

So, mean = $\frac{x=98=98+y}{4}=400\\\frac{196+x+y}{4}=100\\x+y=400-196\\x-y=204$

So our 2nd equation becomes

x+y=204

On using elimination method of system of linear equation on these two equation we get,

x=97

and

$x+y=204\\y=204-x\\y=204-97\\y=107$

Hence , remaining two observation becomes 97 and 107.

8 0

2 years ago

The article "Expectation Analysis of the Probability of Failure for Water Supply Pipes"† proposed using the Poisson distribution

oksian1 [2.3K]

Answer:

a. P(X ≤ 5) = 0.999

b. P(X > λ+λ) = P(X > 2) = 0.080

Step-by-step explanation:

We model this randome variable with a Poisson distribution, with parameter λ=1.

We have to calculate, using this distribution, P(X ≤ 5).

The probability of k pipeline failures can be calculated with the following equation:

$P(k)=\lambda^{k} \cdot e^{-\lambda}/k!=1^{k} \cdot e^{-1}/k!=e^{-1}/k!$

Then, we can calculate P(X ≤ 5) as:

$P(X\leq5)=P(0)+P(1)+P(2)+P(4)+P(5)\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\P(3)=1^{3} \cdot e^{-1}/3!=1*0.3679/6=0.061\\\\P(4)=1^{4} \cdot e^{-1}/4!=1*0.3679/24=0.015\\\\P(5)=1^{5} \cdot e^{-1}/5!=1*0.3679/120=0.003\\\\\\P(X\leq5)=0.368+0.368+0.184+0.061+0.015+0.003=0.999$

The standard deviation of the Poisson deistribution is equal to its parameter λ=1, so the probability that X exceeds its mean value by more than one standard deviation (X>1+1=2) can be calculated as:

$P(X>2)=1-(P(0)+P(1)+P(2))\\\\\\P(0)=1^{0} \cdot e^{-1}/0!=1*0.3679/1=0.368\\\\P(1)=1^{1} \cdot e^{-1}/1!=1*0.3679/1=0.368\\\\P(2)=1^{2} \cdot e^{-1}/2!=1*0.3679/2=0.184\\\\\\P(X>2)=1-(0.368+0.368+0.184)=1-0.920=0.080$

4 0

2 years ago

A poll conducted a week before the school election to the student council showed that Janice would win with 63% of the vote. The

k0ka [10]

OPTIONS:

No, because she could receive as low as 14% of the vote.

No, because she could receive as low as 49% of the vote.

Yes, because she could receive as much as 77% of the vote.

Yes, because the poll stated that she will win with 63% of the vote.

Answer:

No, because she could receive as low as 49% of the vote.

Step-by-step explanation:

Given that:

Poll suggestion = 63%

Margin of Error (E) = 14%

This means that; the range or interval in which the vote obtained could fall would be ;

Poll suggestion ± margin of Error

63% ± 14%

Lower bound attainable = (63% - 14%) = 49%

Upper bound attainable = (63% + 14%) = 77%

Since, winning actually requires obtaining atleast half of the votes (that is 50%) ; and suggested poll suggested votes could fall as low as 49% ; then Janice can't be so confident of victory.

8 0

2 years ago

Milk and cream are mixed together for a recipe. The total volume of the mixture is 1 cup. If the milk contains 2% fat, the cream

inessss [21]

Answer: 1/4

Step-by-step explanation:

Let the volume of mixture (6%fat) in cup is 100cc

x cc be the volume of cream (18% fat) in the mixture.

∴

(100−x) cc be the volume of milk (2% fat) in the mixture.

x * 0.18+(100−x) * 0.02=100

⋅0.06 or 0.18x − 0.02x = 6−2 or 0.16x

= 4 or x=25 cc = 25%

7 0

1 year ago

Read 2 more answers