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2 years ago

Victoria bought 14 chicken wings for $19.60. If Victoria spent $23.80, how many

Mathematics

2 answers:

kykrilka [37]2 years ago

7 0

She buys 17 chicken wigs

Olenka [21]2 years ago

3 0

Answer:

She buys 17 chickens

Step-by-step explanation:

hope this helps:)

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The Earth is one astronomical unit from the sun i.e.1AU= 93 million miles.The angular speed of the Earth traveling around the su

Wewaii [24]

Answer: 0.0667117 * $10^{6}$ miles

Step-by-step explanation: The Earth is one astronomical unit from the sun i.e.1AU= 93 million miles.The angular speed of the Earth traveling around the sun is approximately 0.9863 degrees per day. If we assume the orbit of the Earth is completely circular, what is the linear speed in miles per hour?

Step-by-step explanation: First, a day has 24 hours. Knowing how far the earth travels in day we can say:

0,9863 degrees/day = 0,9863 degrees/(24 hours)

0,9863 degrees/day = 0.0411 degrees/hours

Also, we know the orbit completely circular, so the total distance on, degrees, is 360°. Also this distance can be know with the formula:

Total Circuference = 360° = 2*pi* R

Because Radius is variable for any circle. It is say that:

360° = 2*pi radians

WIth this relation, we can know how many radians are 0.0411 degrees

360/0.0411 = (2*pi)/x

x = (2*pi*0.0411)/(360)

X = 0.00071733032

X is how much the Earth travels per hour in Radians.

Multiplying per Radius:

Earth distance traveled per hour = 0.0667117 * $10^{6}$ miles

8 0

2 years ago

A linear function that represents the number of hot dogs purchased at a football game is compared to a different linear function

Vsevolod [243]

Answer:

Key features: the functions can not be parallels, this means that their respective slopes can not be equal or multiple to the other

Step-by-step explanation:

Take for instance 2 linear functions, and

If they intersect in some point in the space, say that is

Then (x1,y1)=(x3,y3), (x2.y2)= (x3,y3)

So, we can compare the two functions and get the following result;

It tells us that if M=m, we get an error, meaning that the functions are in fact parallels and there is no way that they meet in some point.

hope this helps!

5 0

2 years ago

The mean GPA of student in a course at UCDevis is 3.2 with a standard deviation of 0.3. What percent of student in a course have

Orlov [11]

Answer:

81.86%

Step-by-step explanation:

We are given that the mean GPA of students in a course at UC Davis is 3.2 with a standard deviation of 0.3.

Assuming that the data follows normal distribution.

Let X = GPA of students in a course at UC Davis

So, X ~ Normal()

The z score probability distribution for normal distribution is given by;

Z = ~ N(0,1)

where, = population mean GPA = 3.2

= standard deviation = 0.3

Now, the probability that the students in the course have a GPA between 2.9 and 3.8 is given by = P(2.9 < X < 3.8)

P(2.9 < X < 3.8) = P(X < 3.8) - P(X 2.9)

P(X < 3.8) = P( < ) = P(Z < 2) = 0.97725

P(X 2.9) = P( ) = P(Z -1) = 1 - P(Z < 1)

= 1 - 0.84134 = 0.15866

The above probability is calculated by looking at the value of x = 2 and x = 1 in the z table which has an area of 0.97725 and 0.84134 respectively.

Therefore, P(2.9 < X < 3.8) = 0.97725 - 0.15866 = 0.8186

Hence, 81.86% of students in the course have a GPA between 2.9 and 3.8.

5 0

2 years ago

The segments shown below could form a triangle.

Rina8888 [55]

Answer:

A. True

Step-by-step explanation:

The Triangle Inequality Theorem says that the sum of any two sides must be greater than the third side. Let's see if this is true.

a + b

9 + 1 = 10>9

a + c

9 + 9 = 18>1

c + b

9 + 1 = 10>9

5 0

2 years ago

In a golf tournament, Sam played 4 rounds and was within 2 strokes of par for all 4 rounds of the tournament. If par is 72 on th

In-s [12.5K]

Given:

$|x-4(72)|=2$

To find:

The highest and lowest scores Sam could have made in the tournament.

Solution:

We have,

$|x-4(72)|=2$

$|x-288|=2$

It can be written as

$x-288=\pm 2$

Add 288 on both sides.

$x=288\pm 2$

$x=288-2$ and $x=288+2$

$x=286$ and $x=290$

Therefore, the highest and lowest scores Sam could have made in the tournament are 290 and 286 respectively.

8 0

2 years ago