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otez555 [7]
2 years ago
13

Kim solved the equation below by graphing a system of equations. log2(3x-1)= log4(x+8) What is the approximate solution to the e

quation?

Mathematics
2 answers:
dem82 [27]2 years ago
8 0

Answer:

The solution to the given equation is at point (1.353, 1.613).        

Step-by-step explanation:

Given : Kim solved the equation below by graphing a system of equations.

\log_2(3x-1)=\log_4(x+8)

To find : What is the approximate solution to the equation?

Solution :

Let, y_1=\log_2(3x-1)

and  y_2=\log_4(x+8)

Now, we plot these two equations.

The graph of y_1=\log_2(3x-1) is shown with green line.

The graph of y_2=\log_4(x+8) is shown with violet line.

The solution to this system will be their intersection point.

The intersection point of these graph is (1.353, 1.613)

Refer the attached graph below.

Therefore, The solution to the given equation is at point (1.353, 1.613).

kifflom [539]2 years ago
6 0

Answer:

(1.35, 1.6)

Step-by-step explanation:

A screenshot of the graph is attached.

Once we graph the equations y=\log_2(3x-1) and y=\log_4(x+8), the solution to this system will be their intersection point.

Tracing the graph on the calculator, we see that the point of intersection is at about (1.35, 1.6).

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Stephanie has $45,000. Part or all of which she wants to invest into a combination of municipal bonds and corporate bonds. She w
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Answer:

Step-by-step explanation:

Let x be the amount invested in municipal bonds, and let y be the amount invested in corporate bonds.

If Stephanie has $45,000 and she wants to invest part or all into a combination of municipal bonds and corporate bonds, the inequality for this statement would be

x + y ≤ 45000

She wants to invest no less than $20,000 into municipal bonds. It means that

x ≥ 20000

Also, she wants to invest at least four times as much into municipal bonds than into corporate bonds. This means that

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The inequalities are

x + y ≤ 45000

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8 0
2 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
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Answer:

A. StartFraction (x + 5) (x + 2) Over x cubed minus 9 x EndFraction

Step-by-step explanation:

Given:

(2x + 5) / (x² - 3x) - (3x + 5) / (x³ - 9x) - (x + 1) / x² - 9

Factor the denominators

(2x + 5) / x(x - 3) - (3x + 5) / x(x - 3)(x + 3) - (x + 1) / (x - 3)(x + 3)

Lowest common multiple of the 3 fractions is x(x - 3)(x + 3)

= (2x+5)(x+3) - (3x + 5) - (x + 1)x / x(x - 3)(x + 3)

= (2x²+6x+5x+15) - (3x + 5) - (x² + x) / x(x - 3)(x + 3)

= 2x² + 11x + 15 - 3x - 5 - x² - x / x(x - 3)(x + 3)

= x² + 7x + 10 / x(x - 3)(x + 3)

Solve the numerator.

Solve the quadratic expression by finding two numbers whose product is 10 and sum is 7

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= x² + 5x + 2x + 10 / x(x - 3)(x + 3)

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A. StartFraction (x + 5) (x + 2) Over x cubed minus 9 x EndFraction

Recall,

x(x - 3)(x + 3) is a factor of x³ - 8x

A. StartFraction (x + 5) (x + 2) Over x cubed minus 9 x EndFraction

(x + 5)(x + 2) / x³ - 9x

B. StartFraction (x + 5) (x + 4) Over x cubed minus 9 x EndFraction

(x + 5)(x + 4) / x³ - 9x

C. StartFraction negative 2 x + 11 Over x cubed minus 12 x minus 9 EndFraction

2x + 11 / x³ - 12x - 9

D. StartFraction 3 (x + 2) Over x squared minus 3 x EndFraction

3(x + 2) / x² - 3x

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