What was her starting average? 93 points
How much did her average increase or decrease, overall? 5 points
What was her final average? 83 points
One pattern that you can see in a multiplication table is the perfect square numbers. It runs from the top left hand corner directly through the middle to the bottom right hand corner. A perfect square is a number that is multiplied by itself. The perfect square numbers are 1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144. They keep going forever on but those are the main ones from 1x1 to 12x12.
Answer:
Shift 2 unit left
Flip the graph about y-axis
Stretch horizontally by factor 2
Shift vertically up by 2 units
Step-by-step explanation:
Given:
Parent function: 
Transformation function: 
Take -2 common from transform function f(x)
![f(x)=\log[-2(x+2)]+2](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D%2B2)
Now we see the step-by-step translation

Shift 2 unit left ( x → x+2 )

Flip the graph about y-axis ( (x+2) → - (x+2) )
![f(x)=\log[-(x+2)]](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-%28x%2B2%29%5D)
Stretch horizontally by factor 2 [ -x(x+2) → -2(x+2) ]
![f(x)=\log[-2(x+2)]](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D)
Shift vertically up by 2 units [ f(x) → f(x) + 2 ]
![f(x)=\log[-2(x+2)]+2](https://tex.z-dn.net/?f=f%28x%29%3D%5Clog%5B-2%28x%2B2%29%5D%2B2)
Simplify the function:

Hence, Using four step of transformation to get new function 
Answer:
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).
Step-by-step explanation:
Intern No. of Breast
Number Exams Performed X²
1 30 900
2 40 1600
3 8 64
4 20 400
5 26 676
6 35 1225
7 35 1225
8 20 400
9 25 625
<u>10 20 400 </u>
<u> </u><u> ∑ 259 ∑ 7515</u>
Mean= X`= ∑x/n= 259/10= 25.9
Variance = s²= 1/n-1[∑X²- (∑x)²/n]
= 1/0[7515- (259)²/10]= 1/9[7515- 6708.1]
= 806.9/9=89.655= 89.66
Standard Deviation= √89.655= 9.4687
Hence
The value of t with significance level alpha= 0.05 and 9 degrees of freedom is t(0.025,9)= 2.262
The 95 % Confidence interval is given by
x`±t(∝,n-1) s/√n
So Putting the values
25.9± 2.262( 9.4687/√10)
= 25.9 ±2.262 (2.9943)
= 25.9 ± 6.7730
= 25.9 +6.7730=32.6730
25.9 -6.7730= 19.1269
= 19.1269, 32.6730
The 95 percent confidence interval for the mean of the population from which the study subjects may be presumed to have been drawn is (19.1269, 32.6730).