Jeff has 8 red marbles, 6 blue marbles, and 4 green marbles that are the same size and

Line AB has an equation of a line y = 5x − 2. Which of the following could be an equation for a line that is parallel to line AB

SpyIntel [72]

Determine the slope of line AB
m = 5

Determine the slope of the lines from the options
First option: y = 5x + 3, the slope is 5
Second option: y = (1/5)x + 3, the slope is 1/5
Third option: y = -5x + 3, the slope is -5
Fourth option: y = (-1/5)x + 3, the slope is -1/5

Parallel lines are similar in the slope. So the line which is parallel to line AB must have the slope of 5.

The answer is first option.

4 0

2 years ago

Sally's Stuffed Animal Company charges $0.75 per pound to ship stuffed animals. Part A: Write an equation to determine the total

zalisa [80]

Hope this helps but I think it might be:
Part A: c=0.75p
the cost of shipping for 2 pounds
c=0.75p
c=0.75*2
c=$1.50
Part B: c=0.05p

6 0

2 years ago

6. Two observers, 7220 feet apart, observe a balloonist flying overhead between them. Their measures of the

MaRussiya [10]

Answer:

The ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

Step-by-step explanation:

Let's call:

h the height of the ballonist above the ground,

a the distance between the two observers,

$a_1$ the horizontal distance between the first observer and the ballonist

$a_2$ the horizontal distance between the second observer and the ballonist

$\alpha _1$ and $\alpha _2$ the angles of elevation meassured by each observer

S the area of the triangle formed with the observers and the ballonist

So, the area of a triangle is the length of its base times its height.

$S=a*h$ (equation 1)

but we can divide the triangle in two right triangles using the height line. So the total area will be equal to the addition of each individual area.

$S=S_1+S_2$ (equation 2)

$S_1=a_1*h$

But we can write $S_1$ in terms of $\alpha _1$ , like this:

$\tan(\alpha _1)=\frac{h}{a_1} \\a_1=\frac{h}{\tan(\alpha _1)} \\S_1=\frac{h^{2} }{\tan(\alpha _1)}$

And for $S_2$ will be the same:

$S_2=\frac{h^{2} }{\tan(\alpha _2)}$

Replacing in the equation 2:

$S=\frac{h^{2} }{\tan(\alpha _1)}+\frac{h^{2} }{\tan(\alpha _2)}\\S=h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})$

And replacing in the equation 1:

$h^{2}*(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})=a*h\\h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}$

So, we can replace all the known data in the last equation:

$h=\frac{a}{(\frac{1 }{\tan(\alpha _1)}+\frac{1}{\tan(\alpha _2)})}\\h=\frac{7220 ft}{(\frac{1 }{\tan(35.6)}+\frac{1}{\tan(58.2)})}\\h=3579,91 ft$

Then, the ballonist is at a height of 3579.91 ft above the ground at 3:30pm.

6 0

2 years ago

A researcher is estimating the mean income of residents in a large city. The income variable is usually skewed to the right. She

Gnom [1K]

Answer: We are 95% confident that the mean income for all residents of this city is between $26700 and $35400.

Step-by-step explanation:

We know that a 95% confidence interval given an interval of values that we can be 95% sure , that it contains the true mean of the population, not 95% of data lies in it.

Given : A researcher is estimating the mean income of residents in a large city. The income variable is usually skewed to the right. She collects a random sample of 25 people.

The resulting 95% confidence interval is ($26700, $35400).

Then, valid conclusion will be : We are 95% confident that the mean income for all residents of this city is between $26700 and $35400.

5 0

2 years ago

Ming needs 1/2 pint of red paint for an art project. He has 6 jars that have the following amounts of red paint in them. He want

Dmitrij [34]

The possible answers are A C and D because they all have at least a half pint of paint.

5 0

2 years ago

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