Add 8π to both sides of the equation to get:
We have found that x = 9π. Remember that in solving problems like these with pi that it can often be helpful to treat pi as a variable.
Answer:
a) Adding -5x on both sides of the equation to remove the smaller x-coefficient
b) Adding -4 on both sides will remove the constant from the right side of the equation
Step-by-step explanation:
Given equation:
5x + (−2) = 6x + 4
a) What tiles need to be added to both sides to remove the smaller x-coefficient?
Smaller x-coefficient is 5x to remove the smaller x-coefficient
So, Adding -5x on both sides of the equation to remove the smaller x-coefficient
b) What tiles need to be added to both sides to remove the constant from the right side of the equation?
the constant on right side is 4
Adding -4 on both sides will remove the constant from the right side of the equation
Answer:
<u>The correct answer is D. Any amount of time over an hour and a half would cost $10.</u>
Step-by-step explanation:
f (t), when t is a value between 0 and 30
The cost is US$ 0 for the first 30 minutes
f (t), when t is a value between 30 and 90
The cost is US$ 5 if the connection takes between 30 and 90 minutes
f (t), when t is a value greater than 90
The cost is US$ 10 if the connection takes more than 90 minutes
According to these costs, statements A, B and C are incorrect. The connection doesn't cost US$ 5 per hour like statement A affirms, the cost of the connection isn't US$ 5 per minute after the first 30 minutes free as statement B affirms and neither it costs US$ 10 for every 90 minutes of connection, as statement C affirms. <u>The only one that is correct is D, because any amount of time greater than 90 minutes actually costs US$ 10.</u>
The paraboloid meets the x-y plane when x²+y²=9. A circle of radius 3, centre origin.
<span>Use cylindrical coordinates (r,θ,z) so paraboloid becomes z = 9−r² and f = 5r²z. </span>
<span>If F is the mean of f over the region R then F ∫ (R)dV = ∫ (R)fdV </span>
<span>∫ (R)dV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] rdrdθdz </span>
<span>= ∫∫ [θ=0,2π, r=0,3] r(9−r²)drdθ = ∫ [θ=0,2π] { (9/2)3² − (1/4)3⁴} dθ = 81π/2 </span>
<span>∫ (R)fdV = ∫∫∫ [θ=0,2π, r=0,3, z=0,9−r²] 5r²z.rdrdθdz </span>
<span>= 5∫∫ [θ=0,2π, r=0,3] ½r³{ (9−r²)² − 0 } drdθ </span>
<span>= (5/2)∫∫ [θ=0,2π, r=0,3] { 81r³ − 18r⁵ + r⁷} drdθ </span>
<span>= (5/2)∫ [θ=0,2π] { (81/4)3⁴− (3)3⁶+ (1/8)3⁸} dθ = 10935π/8 </span>
<span>∴ F = 10935π/8 ÷ 81π/2 = 135/4</span>
Answer: Barbarino's rentals has a better deal.
She has to drive 887.5 miles to spend the same amount at either company.
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
<em>Mr.kotters rentals (A)
</em>
- <em>$99 PER WEEK
</em>
- <em>$0.11per mile over 100 miles
</em>
<em>Barbarino's rentals (B)
</em>
- <em>$75 per week
</em>
- <em>$0.15 per mile over 150 miles
</em>
For "A"
Cost = 0.11 (432-100) + 99 = $135.52
For "B"
Cost= 0.15 (432-150) +75 = $117.3
Barbarino's rentals has a better deal, since $117.3(B) < $135.52 (A)
To find how many miles would Glenna drive before she would be spending the same amount at either company:
A =B
0.11 (M-100) + 99 =0.15 (M-150) +75 = $117.3
Solving for M (miles)
0.11 M -11+99 = 0.15 M -22.5+75
-11 +99 +22.5 -75 =0.15M -0.11 M
35.5 = 0.04M
35.5/0.04 = M
887.5 =M
She has to drive 887.5 miles to spend the same amount at either company.
