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Bad White [126]
1 year ago
13

Concentric circles are circles with the same center but different radii. Which equations represent concentric circles along with

the circle shown in the graph? Check all that apply.
x2 + y2 = 25
(x – 8)² + (y – 9)² = 3
(x – 8)² + (y – 9)² = 14
(x – 8)² + (y + 9)² = 3
(x + 8)² + (y + 9)² = 25
(x + 9)² + (y + 8)² = 3
Mathematics
2 answers:
Harrizon [31]1 year ago
7 0
<span>(x – 8)² + (y – 9)² = 3
(x – 8)² + (y – 9)² = 14
</span>are the correct answers
Alexus [3.1K]1 year ago
4 0

As given Concentric circles are those circles having same center but having different radii.

General equation of Circle → (x-a)² + (y-b)² = r², Center = (a,b),Radius = r

1. x ²+ y² = 25

→ ( x-0) ²+ (y-0)² = 5²  , center  = (0,0), Radius = 5

2.(x – 8)² + (y – 9)² = 3

→(x – 8)² + (y – 9)² = (√3 )², Center =(8,9), Radius = √3

3.  (x – 8)² + (y – 9)² = 14

→ (x – 8)² + (y – 9)² = [√14]², center = (8,9),Radius = √14

4. (x – 8)² + (y + 9)² =

→ (x – 8)² + (y + 9)² = [√3]², Center = (8,9), Radius = √3

5. (x + 8)² + (y + 9)² = 25

→(x + 8)² + (y + 9)² = 5² , Center = (-8,-9),Radius = 5

6. (x + 9)² + (y + 8)² = 3

→(x + 9)² + (y + 8)² = [√3]², Center = (-9,-8), Radius = √3

⇒Circle (2)→(x – 8)² + (y – 9)² = (√3 )², Center =(8,9), Radius = √3 and Circle 3 which is → (x – 8)² + (y – 9)² = [√14]², center = (8,9),Radius = √14 are Concentric.

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good job on increasing our team sales from 90 to 130 units per day.” wow i never thought that we could increase our sales by
artcher [175]

The sales was increased by 44.4%.

Step-by-step explanation:

  • Lets do this cumulative
  • 90 of 10 % =  9  which is 99
  • 90 of 10 % = 9 which is 108
  • 90 of 10% = 9 which is 117
  • 90 of 10% = 9 which is 126
  • 90 of 4 % = 3.6 which is 129.6
  • 90 of 0.044% = 0.0396 which is 129.99
  • This comes to nearly 44.44 to be closer there was an increase.
  • Always rule 1 approximation use 50% of 90 if it is above 130.
  • Down it to 40% of 90 see if the sales is lower than 130.
  • It should always start with 50,40,30....10 percents.
  • Alternative should be 10,1 or decimals.
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7 0
1 year ago
Which of the following systems of Inequalities would produce the region indicated on the graph below?
Fed [463]
The line rising to the right has equation y = x + 2
and the  other one has equation y =  -x + 4

the lines are solid so the inequalities will be <= or >=

in both case  the shading is below so the sign is <=

also x and Y values are both positive  
so the answer is choice  C

7 0
2 years ago
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Answer:

The answer is the bottom graph on the left. :)

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1 year ago
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Jack bought 4 dozen eggs at $10 per dozen. 6 were broken. what percent of his money goes to waste
Korvikt [17]

So, if he has 4 dozen eggs, ten dollars per dozen, he has spent $40 on 48 eggs. <em>This means the cost of one egg = 48/40. </em>This can simplify to <em>6/5 </em>which is equal to<em> $1.20. </em>This means the value of one egg is $1.20, including the broken ones! So if six were broken, we multiply 1.20 x 6 which equals <em>$7.20!</em>

Use this "formula" to help find percentages

<em>Part/Total = %( Percentage )/ 100</em>

Now that we know how much money has gone to waste, we can plug in the known values into this "formula."

<em>7.2/48 = x/100</em>

Solve accordingly; cross multiply, 720 = 48x; divide both sides of the equation by 48 to isolate the variable, 720/48 = 48x/48; now you have your final answer which is:

15 = x; going back to the "formula" this means 15% of his money has gone to waste. I hope this helped! :)

5 0
1 year ago
Which of the following events are equal? (a) A = {1,3}; (b) B = {x | x is a number on a die }; (c) C = {x | x2 −4x +3=0 }; (d) D
rosijanka [135]

Answer:

A and C

Step-by-step explanation:

To determine which events are equal, we explicitly define the elements in each set builder.

For event A

A={1.3}

for event B

B={x|x is a number on a die}

The possible numbers on a die are 1,2,3,4,5 and 6. Hence event B is computed as

B={1,2,3,4,5,6}

for event C

C=[x|x^{2}-4x+3]\\solving  x^{2}-4x+3\\x^{2}-4x+3=0\\x^{2}-3x-x+3=0\\x(x-3)-1(x-3)=0\\x=3 or x=1

Hence the set c is C={1,3}

and for the set D {x| x is the number of heads when six coins re tossed }

In the tossing a six coins it is possible not to have any head and it is possible to have head ranging from 1 to 6

Hence the set D can be expressed as

D={0,1,2,3,4,5,6}

In conclusion, when all the set are compared only set A and set C are equal

5 0
2 years ago
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