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Bad White [126]
2 years ago
13

Concentric circles are circles with the same center but different radii. Which equations represent concentric circles along with

the circle shown in the graph? Check all that apply.
x2 + y2 = 25
(x – 8)² + (y – 9)² = 3
(x – 8)² + (y – 9)² = 14
(x – 8)² + (y + 9)² = 3
(x + 8)² + (y + 9)² = 25
(x + 9)² + (y + 8)² = 3
Mathematics
2 answers:
Harrizon [31]2 years ago
7 0
<span>(x – 8)² + (y – 9)² = 3
(x – 8)² + (y – 9)² = 14
</span>are the correct answers
Alexus [3.1K]2 years ago
4 0

As given Concentric circles are those circles having same center but having different radii.

General equation of Circle → (x-a)² + (y-b)² = r², Center = (a,b),Radius = r

1. x ²+ y² = 25

→ ( x-0) ²+ (y-0)² = 5²  , center  = (0,0), Radius = 5

2.(x – 8)² + (y – 9)² = 3

→(x – 8)² + (y – 9)² = (√3 )², Center =(8,9), Radius = √3

3.  (x – 8)² + (y – 9)² = 14

→ (x – 8)² + (y – 9)² = [√14]², center = (8,9),Radius = √14

4. (x – 8)² + (y + 9)² =

→ (x – 8)² + (y + 9)² = [√3]², Center = (8,9), Radius = √3

5. (x + 8)² + (y + 9)² = 25

→(x + 8)² + (y + 9)² = 5² , Center = (-8,-9),Radius = 5

6. (x + 9)² + (y + 8)² = 3

→(x + 9)² + (y + 8)² = [√3]², Center = (-9,-8), Radius = √3

⇒Circle (2)→(x – 8)² + (y – 9)² = (√3 )², Center =(8,9), Radius = √3 and Circle 3 which is → (x – 8)² + (y – 9)² = [√14]², center = (8,9),Radius = √14 are Concentric.

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1.4 × 10^-8

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Answer:

c = 34/d

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Step-by-step explanation:

Part A

Basic Formula

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Part B

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d = ?

68 = 34/d               Multiply both sides by d

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Dividing both sides by 16:
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For ΔA'B'C', we have
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madreJ [45]

Answer:

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\mu =90 , \sigma =14

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

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b. 2 minutes

Step-by-step explanation:

Previous concepts

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Solution to the problem

For this case we have the following info related to the time to prepare a return

\mu =90 , \sigma =14

And we select a sample size =49>30 and we are interested in determine the standard deviation for the sample mean. From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation would be:

\sigma_{\bar X} =\frac{14}{\sqrt{49}}= 2

And the best answer would be

b. 2 minutes

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