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Bad White [126]
2 years ago
13

Concentric circles are circles with the same center but different radii. Which equations represent concentric circles along with

the circle shown in the graph? Check all that apply.
x2 + y2 = 25
(x – 8)² + (y – 9)² = 3
(x – 8)² + (y – 9)² = 14
(x – 8)² + (y + 9)² = 3
(x + 8)² + (y + 9)² = 25
(x + 9)² + (y + 8)² = 3
Mathematics
2 answers:
Harrizon [31]2 years ago
7 0
<span>(x – 8)² + (y – 9)² = 3
(x – 8)² + (y – 9)² = 14
</span>are the correct answers
Alexus [3.1K]2 years ago
4 0

As given Concentric circles are those circles having same center but having different radii.

General equation of Circle → (x-a)² + (y-b)² = r², Center = (a,b),Radius = r

1. x ²+ y² = 25

→ ( x-0) ²+ (y-0)² = 5²  , center  = (0,0), Radius = 5

2.(x – 8)² + (y – 9)² = 3

→(x – 8)² + (y – 9)² = (√3 )², Center =(8,9), Radius = √3

3.  (x – 8)² + (y – 9)² = 14

→ (x – 8)² + (y – 9)² = [√14]², center = (8,9),Radius = √14

4. (x – 8)² + (y + 9)² =

→ (x – 8)² + (y + 9)² = [√3]², Center = (8,9), Radius = √3

5. (x + 8)² + (y + 9)² = 25

→(x + 8)² + (y + 9)² = 5² , Center = (-8,-9),Radius = 5

6. (x + 9)² + (y + 8)² = 3

→(x + 9)² + (y + 8)² = [√3]², Center = (-9,-8), Radius = √3

⇒Circle (2)→(x – 8)² + (y – 9)² = (√3 )², Center =(8,9), Radius = √3 and Circle 3 which is → (x – 8)² + (y – 9)² = [√14]², center = (8,9),Radius = √14 are Concentric.

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Step-by-step explanation:

a. According to the given data we can conclude that the null hypothesis for this test is that the observed distribution is the same as uniform distribution.

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The calculated value of the test statistic is 9.250

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From my research, the image attached supports the problem. Since only the outer curve is to be solved for, the formula for arcs can be used.

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When x = 6.4, y=117, therefore

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Question:

Read the excerpt from Julius Caesar, act 1, scene 2.

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