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iVinArrow [24]
2 years ago
14

The number 8/7 = 1.14285714285714 ... obviously has no exact representation in any decimal floating point system (beta = 10) wit

h finite precision t. Is there a finite floating point system (i.e., some finite integer base beta and precision t) in which this number does have an exact representation? If yes, then describe such a system. Answer the same question for the irrational number pi.
Mathematics
1 answer:
arlik [135]2 years ago
5 0

Answer:

The answer to this question can be defined as follows:

Step-by-step explanation:

In the first point:

Yes, the Finite Floating Point Structures are considered  Where \beta = 7

\to \frac{8}{7}= (1.1)_7

\bold{= 1 \times 7^0 + 1 \times 7^{-1}}\\\\

In the second point:

There is no device with a finite floating-point since the right side is  

This equality never happens, then, with the rational numbers (\alpha_i and \beta is rational).

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If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t circle s) (x)?
Georgia [21]

Answer:

If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t*s)(x)? 4(x – 7)2 – x – 7 + 3 4(x – 7)2 – (x – 7) + 3 (4x2 – x + 3) – 7 (4x2 – x + 3)(x – 7)

8 0
1 year ago
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A rectangular floor tile is shown it dimensions are given to the nearest 0.1 metres the tile is only able to sustain maximum pre
egoroff_w [7]

Answer:

736 N

Step-by-step explanation:

The dimensions of the rectangular tile are:

Length = 2.3m

Width = 1.6m

The pressure exerted on a surface is given by the formula

p=\frac{F}{A}

where

p is the pressure

F is the force exerted

A is the area on which the force is exerted

In this problem, we have:

p=200 N/m^2 is the maximum pressure that the tile is able to sustain

A is the area of the tile, which can be calculated as the product between length and width, so:

A=L\cdot w =(2.3)(1.6)=3.68 m^2

Re-arranging the formula for F, we can find the maximum force that can be safely applied to the tile:

F=pA=(200)(3.68)=736 N

4 0
1 year ago
baker has 5\dfrac145 4 1 ​ 5, start fraction, 1, divided by, 4, end fraction pies in her shop. She cut the pies in pieces that a
kupik [55]

Answer:

The answer is "She cut a total of 42 pieces of pie".

Step-by-step explanation:

Given :

Total pie=  5 \frac{1}{4}

cut pie = \frac{1}{8}

The number of pieces of the pie she has=?

Solve the mixed fraction value:

\to 5 \frac{1}{4}= \frac{21}{4}

If she cuts the pieces into the entire pie, that is  = \frac{1}{8}  

So, the equation is:

\to \frac{21}{4} = \frac{1}{8} \times x

\to x= \frac{21 \times 8}{4}\\\\ \to x= 21 \times 2\\\\ \to  x=42

7 0
1 year ago
Solve the equation 4x2 + 2 = 38 using square roots.
hammer [34]

Answer:

Step-by-step explanation:

Tiger Algebra gives you not only the answers, but also the complete step by step method for solving your equations 4x^2-2=38 so that you ... Step 2 : Step 3 :Pulling out like terms. 3.1 Pull out like factors : 4x2 - 40 = 4 • (x2 - 10) ... x2 = 10. When two things are equal, their square roots are equal.

3 0
1 year ago
A freight company has shipping orders for two products. The first product has a unit volume of 10 cu ft, and it weighs 50 lbs. T
Lady_Fox [76]

Answer:

116 units of the first product

380 units of the second product

Step-by-step explanation:

Product 1 has a unit volume of  10 cu ft

Product 2 has a unit volume of 3 cu ft

The truck has 2300 cu ft of space

Product 1 weighs 50 lbs

Product 2 weighs 40 lbs

The truck can carry 21000 lbs

Let X be the units of product 1

Let Y be the units of product 2

The given information can be expressed as:

10X+3Y=2300...(1)

50X+40Y=21000...(2)

Solving the system of equations:

10X+3Y=2300...(1)

10X=2300-3Y

X=(2300-3Y)/10

Substituting X in (2) we have:

50X+40Y=21000

50[(2300-3Y)/10]+40Y=21000

50[(2300/10)-(3Y/10)]+40Y=21000

50[230-(3Y/10)+40Y=21000

11500-(150Y/10)+40Y=21000

11500-15Y+40Y=21000

11500+25Y=21000

25Y=21000-11500

25Y=9500

Y=380

Substituting Y in (1) we have:

10X+3Y=2300...(1)

10X+3(380)=2300

10X+1140=2300

10X=2300-1140

10X=1160

X=116

So 116 units of the first product and 380 units of the second product can be transported in a single shipment with one truck.

8 0
2 years ago
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