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sammy [17]
2 years ago
15

Select all the values that belong to the solution set of 9 ≤ 6 - y.

Mathematics
1 answer:
Veseljchak [2.6K]2 years ago
7 0
All you have to do is substitute the values in for y to see if they are true.

0: 9 ≤ 6 - 0 = 9 ≤ 6 (FALSE)
3: 9 ≤ 6 - 3 = 9 ≤ 3 (FALSE)
-3: 9 ≤ 6 - -3 = 9 ≤ 9 (TRUE)
-1: 9 ≤ 6 - -1 = 9 ≤ 7 (FALSE)
-6: 9 ≤ 6 - -6 = 9 ≤ 12 (TRUE)
6: 9 ≤ 6 - 6 = 9 ≤ 0 (FALSE)
-4: 9 ≤ 6 - -4 = 9 ≤ 10 (TRUE)

So, the values that belong to 9 ≤ 6 - y are -3, -4, and -6.


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The <em><u>correct answer</u></em> is:

She can determine that while there is an association between the variables, there is no correlation, and she cannot determine causation.

Explanation:

Since there is an arch shape to her graph, we know that as one variable changes, the other changes in the same manner. This means there is an association between the variables.

However, since the graph is not linear, there is no correlation between the variables. Since there is no correlation, we cannot determine causation.

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2 years ago
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If VX = WZ = 40 cm and m∠ZVX = m∠XWZ = 22°, can ΔVZX and ΔWXZ be proven congruent by SAS? Why or why not?
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Answer: The ΔVZX and ΔWXZ are not congruent by SAS.

Explanation:

It is given that the VX = WZ = 40 cm and ∠ZVX = ∠XWZ = 22°.

Draw a figure as shown below,

According to the SAS rule of congruence, two triangles are congruent if two sides and their inclined angle is equal.

From the given figure it is easily noticed that in ΔVZX and ΔWXZ,

VX=WZ=40cm       (given)

\angle ZVX=\angle XWZ=22^{\circ}     (given)

XZ=XZ      (common side)

Since we have two sides and one angle is same. but we can not conclude that the ΔVZX and ΔWXZ are congruent by SAS, because the given angle is not the inclined angle of both equal sides.

Therefore, the  ΔVZX and ΔWXZ are not congruent by SAS.

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If the size of the sample to be used in a particular test of attributes has not been determined by utilizing statistical concept
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Answer:

C) The auditor may or may not achieve the desired risk of assessing control risk too low.

Step-by-step explanation:

In a concept of risk sampling, if the sample size is chosen randomly in accordance with random selection procedures, the auditor may or may not achieve the desired risk of assessing risk too low. In other words the auditor may or may not achieve desired precision. This is because a samole chosen randomly may not represent the true population.

This depends largely on the sample size. If the sample size selected is too small, the allowance for sampling risk will be larger than what is required because it will lead to a large standard error of the mean

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For the month of June, Mae Green budgeted the following amounts: $180 for food, $475 for rent, $15 for transportation, $50 for i
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Total budget = 180 + 475 + 15 + 50 + 65 + 25 + 150 + 30 = $990
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Mae Green didn't stay within the allocated budget

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Question 2

Eleanor:
Income = 380.48
Spending = 16.50

Peter:
Income = 120 + 13.65 + 100 = 233.65

Total income = 233.65 + 380.48 - 16.50 = 597.63

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Question 3

Total spent = 540 + 48.55 + 34.15 + 12.80 + 18.95 + 38.60 + 2 + 6.50 = 701.55

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Question 4 

Marie's new balance = 250.65 - [21.95+48.50+75.60] + 55 = $159.50

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Question 5

[235/825] × 100 = 28.48%
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