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2 years ago

a store sells 2 pounds of tomatoes for $7. Write an equation that represents the cost, c, for t pounds of tomatoes

Mathematics

1 answer:

algol132 years ago

5 0

Answer:

t pounds = 3.5 (or just t = 3.5c)

Step-by-step explanation:

2 pounds of tomatos for 7$ means that one pound of tomatos for 3.5$. Therefore, t pounds = 3.5 c

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BRAINLY ANYONE?

Oduvanchick [21]

Answer:

58, 37, 9

Step-by-step explanation:

Given:

First term a₁ = 65 and common difference d = - 7

This sequence is arithmetic series and formula for calculating n-th term is:

aₙ = a₁ + (n-1) d

Accordingly

The second term is:

a₂ = 65 + (2-1) (-7) = 65 - 7 = 58

a₂ = 58

The fifth term is:

a₅ = 65 + (5 - 1) (-7) = 65 + 4 · (-7) = 65 - 28 = 37

a₅ = 37

The ninth term is:

a₉ = 65 + (9 - 1) (-7) = 65 + 8 · (-7) = 65 - 56 = 9

a₉ = 9

God with you!!!

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ludmilkaskok [199]

Answer:

Step-by-step explanation:

7.41 / 0.13 = 57

57 - 15 = 42

42 / 2 = 21

21, 36

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2 years ago

A bowl contains 55 mints. Customers eat 4 mints each hour. Which equation can be used to determine how many hours remain until 2

Nina [5.8K]

Answer:

55-4x=22

Step-by-step explanation:

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Which of the following formulas, when evaluated using rational values for the variables, will result in an irrational number?

gogolik [260]

A. because pi is a irrational #

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2 years ago

See You Later Based on a Harris Interactive poll, 20% of adults believe in reincarnation. Assume that six adults are randomly se

REY [17]

Answer:

a) There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b) 0.0064% probability that all of the selected adults believe in reincarnation.

c) There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d) Since $P(X \geq 5) < 0.05$ , 5 is a significantly high number of adults who believe in reincarnation in this sample.

Step-by-step explanation:

For each of the adults selected, there are only two possible outcomes. Either they believe in reincarnation, or they do not. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

$n = 6, p = 0.2$

a. What is the probability that exactly five of the selected adults believe in reincarnation?

This is P(X = 5).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{6,5}.(0.2)^{5}.(0.8)^{1} = 0.0015$

There is a 0.15% probability that exactly five of the selected adults believe in reincarnation.

b. What is the probability that all of the selected adults believe in reincarnation?

This is P(X = 6).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{6,6}.(0.2)^{6}.(0.8)^{0} = 0.000064$

There is a 0.0064% probability that all of the selected adults believe in reincarnation.

c. What is the probability that at least five of the selected adults believe in reincarnation?

This is

$P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564$

There is a 0.1564% probability that at least five of the selected adults believe in reincarnation.

d. If six adults are randomly selected, is five a significantly high number who believe in reincarnation?

5 is significantly high if $P(X \geq 5) < 0.05$

We have that

$P(X \geq 5) = P(X = 5) + P(X = 6) = 0.0015 + 0.000064 = 0.001564 < 0.05$

Since $P(X \geq 5) < 0.05$ , 5 is a significantly high number of adults who believe in reincarnation in this sample.

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2 years ago