Well we set the perimeter to 120 feet.
This means that 2x+2y=120
Now we know the area of a rectangle is xy so we have to solve for both x and y in the perimeter equation.
2x=120-2y
x=60-y
2y=120-2x
y=60-x
Now we plug these values into our area equation A=xy to get:
A=(60-y)(60-x)
Answer:
Costo final= $412.38
Step-by-step explanation:
Dada la siguiente información:
Costo inicial= $355.5
Recargo de la tarjeta= 16% = 0.16
<u>Para calcular el costo final que debe pagar Silvia, debemos usar la siguiente información:</u>
Costo final= costo inicial*(1 + recargo)
Costo final= 355.5*1.16
Costo final= $412.38
Answer:
They are dependent because we have to select from people who are given cards.
Step By Step Explanation:
So we'll take away people not given cards first den find the probability of selecting people with cards over the total number of people present .
Probability we'll be equal to = number of people with card(C) two persons/total number of people
Where C represent combination
Answer:
Step-by-step explanation:
x, height of men is N(69, 2.8)
Sample size n =150
Hence sample std dev = 
Hence Z score = 
A) Prob that a random man from 150 can fit without bending
= P(X<78) = P(Z<3.214)=1.0000
B) n =75
Sample std dev = 
P(X bar <72) = P(Z<9.28) = 1.00
C) Prob of B is more relevent because average male passengers would be more relevant than a single person
(D) The probability from part (b) is more relevant because it shows the proportion of flights where the mean height of the male passengers will be less than the door height.
To determine whether the corresponding terms of 2 arithmetic sequence's added will give new arithmetic sequence or not, Let' take 2 Arithmetic sequences.
In one first term is a1 and common difference is d1, in the other first term is a2 and common difference is d2.
Now nth term for first sequence = a1+(n-1) d1
nth term for second sequence = a2+(n-1) d2
Now add the 2 terms: a1+(n-1)d1 +a2 +(n-1)d2
= a1+a2 + (n-1)(d1+d2)
This is again new arithmetic sequence with first term a1+a2 and common difference d1+d2.
Hence if we add corresponding terms of 2 arithmetic sequence, we will again get an arithmetic sequence.
