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Mademuasel [1]
1 year ago
12

240 students to 12 teachers as ratio

Mathematics
1 answer:
grigory [225]1 year ago
7 0

Answer:

1 : 20 20 students for every 1 teacher

Step-by-step explanation:

divide both sides by 12

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a garden plot is to contain 240 sq. ft. if its length is to be 3 times its width,what should its dimensions be?
Nastasia [14]
W^2=80
W SQRT80
W=8.94 ANS.FOR THE WIDTH
L=3*8.94=26.83 ANS.FOR THE LENGTH
PROOF:
240=8.94*26.83
240=240

3 0
1 year ago
Which number, when substituted for x, makes the equation 4x+8=164x+8=16 true?
ra1l [238]
X = 2

4x + 8 = 16
      -8     -8
----------------
4x= 8
--     --
4     4
------------
x=2
7 0
1 year ago
Read 2 more answers
A warehouse store sells 4.5​-ounce cans of tuna in packages of 3. A package of 3 cans costs ​$4.32. The store also sells 3.5​-ou
disa [49]

Answer:

The 6.5​-ounce cans offer the largest size at a fair cost and is the best to buy.

Step-by-step explanation:

Size of the 4.5​-ounce cans of tuna in package = 4.5 × 3 = 13.5 ounce

Cost of the package= ​$4.32

Size of the 3.5​-ounce cans = 3.5 × 4 = 14 ounce

Cost of the package= ​$3.92

Size of the 6.5​-ounce cans = 6.5 × 5 = 32.5 ounce

Cost of the package= ​$9.75

The 6.5​-ounce cans offer the largest size and is the best to buy.

7 0
1 year ago
Alexa owns a total of 45 fiction and nonfiction books. If the number of fiction books is 15 more than 4 times the number of nonf
Vikentia [17]
What are the choices?
4 0
1 year ago
Suppose we are interested in bidding on a piece of land and we know one other bidder is interested. The seller announced that th
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

(a)

The bid should be greater than $10,000 to get accepted by the seller. Let bid x be a continuous random variable that is uniformly distributed between

$10,000 and $15,000

The interval of the accepted bidding is [ {\rm{\$ 10,000 , \$ 15,000}], where b = $15000 and a = $10000.

The interval of the provided bidding is [$10,000,$12,000]. The probability is calculated as,

\begin{array}{c}\\P\left( {X{\rm{ < 12,000}}} \right){\rm{ = }}1 - P\left( {X > 12000} \right)\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{12000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{12000}^{15000}\\\end{array}

=1- \frac{[15000-12000]}{5000}\\\\=1-0.6\\\\=0.4

(b)  The interval of the accepted bidding is [$10,000,$15,000], where b = $15,000 and a =$10,000. The interval of the given bidding is [$10,000,$14,000].

\begin{array}{c}\\P\left( {X{\rm{ < 14,000}}} \right){\rm{ = }}1 - P\left( {X > 14000} \right)\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{15000 - 10000}}} dx\\\\ = 1 - \int\limits_{14000}^{15000} {\frac{1}{{5000}}} dx\\\\ = 1 - \frac{1}{{5000}}\left[ x \right]_{14000}^{15000}\\\end{array} P(X14000)

=1- \frac{[15000-14000]}{5000}\\\\=1-0.2\\\\=0.8

(c)

The amount that the customer bid to maximize the probability that the customer is getting the property is calculated as,  

The interval of the accepted bidding is [$10,000,$15,000],

where b = $15,000 and a = $10,000. The interval of the given bidding is [$10,000,$15,000].

\begin{array}{c}\\f\left( {X = {\rm{15,000}}} \right){\rm{ = }}\frac{{{\rm{15000}} - {\rm{10000}}}}{{{\rm{15000}} - {\rm{10000}}}}\\\\{\rm{ = }}\frac{{{\rm{5000}}}}{{{\rm{5000}}}}\\\\{\rm{ = 1}}\\\end{array}

(d)  The amount that the customer bid to maximize the probability that the customer is getting the property is $15,000, set by the seller. Another customer is willing to buy the property at $16,000.The bidding less than $16,000 getting considered as the minimum amount to get the property is $10,000.

The bidding amount less than $16,000 considered by the customers as the minimum amount to get the property is $10,000, and greater than $16,000 will depend on how useful the property is for the customer.

5 0
2 years ago
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