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Cloud [144]
1 year ago
13

Use the drop down to answer the question about converting 0.ModifyingAbove 64 with bar to a fraction.

Mathematics
2 answers:
PtichkaEL [24]1 year ago
7 0

Answer:

How many repeating digits are in 0.ModifyingAbove 64 with bar?

2

What value is multiplied on both sides of the equals sign?

100

What fraction represents 0.ModifyingAbove 64 with bar?

64/99

Step-by-step explanation:

i got it right. :))

katovenus [111]1 year ago
5 0

Answer:

2

100

64/99

Step-by-step explanation:

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Answer: 28.27 yd²
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A pure acid measuring x liters is added to 300 liters of a 20% acidic solution. The concentration of acid, f(x), in the new subs
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Answer How many liters of a 20% acid solution should be mixed with 30 liters of 50% acid solution in order to obtain a 40% solution. ... x=15 liters 15*(.20 pure acid)=3 liters 30*(.50 pure acid)=15 liters That is 18 liters pure acid That is 45 liters solution *0.45 pure acid=18 liters.

As more pure acid is added, the concentration of acid approaches 0.

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Find the inverse of y=x2-10x
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<span>this is pretty hard but here is your answer 
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y = x^2 - 10x + 25 - 25

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<span> x-5 = +/-sqrt(y+25) </span>

 

<span> And you get TWO inverses: </span>

 

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<span> x = 5 - sqrt(y+25), for x<=5</span>


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A gas stove that normally sells for $749 is on sale at a 30% discount. What is the sale price of the gas stove
Virty [35]
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Find the eccentricity, b. identify the conic, c. give an equation of the directrix, and d. sketch the conic.
densk [106]

Answer:

a) 10/3  

b) hyperbola

c) x = ± 6/5

Step-by-step explanation:

a) A conic section with a focus at the origin, a directrix of x = ±p where p is a positive real number and positive eccentricity (e) has a polar equation:

r=\frac{ep}{1\pm e*cos\theta}

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We have to make it to be in the form r=\frac{ep}{1\pm e*cos\theta}:

r=\frac{12}{3-10cos\theta}\\\\multiply\ both\ sides\ by\ \frac{1}{3} \\\\r=\frac{12*\frac{1}{3}}{(3-10cos\theta)*\frac{1}{3}}\\\\r=\frac{12*\frac{1}{3}}{3*\frac{1}{3}-10cos\theta*\frac{1}{3}}\\\\r=\frac{4}{1-\frac{10}{3}cos\theta } \\\\r=\frac{\frac{10}{3}(\frac{6}{5} ) }{1-\frac{10}{3}cos\theta }

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b) since the eccentricity = 3.33 > 1, it is a hyperbola

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6 0
2 years ago
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