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Svetradugi [14.3K]
2 years ago
5

What is the greatest common factor of 42a5b3, 35a3b4, and 42ab4? 7ab3   6a4b 42a5b4 77a8b7

Mathematics
2 answers:
lbvjy [14]2 years ago
3 0

The <em><u>correct answer</u></em> is:

7ab³

Explanation:

The greatest common factor is the largest thing that each term is divisible by.

The coefficients of our terms are 42, 35 and 42.  Using the prime factorization for each,

42 = 6*7

6 = 2*3

42 = 2*3*7

35 = 5*7

The greatest common factor is 7.

For the variables, each term has at least a¹ and at least b³.  This means that ab³ is part of the GCF; this gives us a GCF of 7ab³.

gogolik [260]2 years ago
3 0

Answer:

7ab^3

Step-by-step explanation:

You might be interested in
If the five digit number aa448 is divisible by 9, what digit does a represent?
kaheart [24]

Answer:

a represent 1

and number is 11448.

Step-by-step explanation:

We know that a number is divisible by 9 if the sum of its digit is divisible by 9.

Given number aa448

sum of 4+4+8 = 16

number divisible by 9, 18 , 27,36

as we see sum of 448 is 16 , hence sum of a+a+4+4+8 should be  number divisible by 9 and greater than 16 which is 18, 27,36

Let see of if sum of digits of aa448 is divisible by  18

a+a+4+4+8 = 18

2a + 16 = 18

2a = 18-16 = 2

a =2/2 = 1

Thus, number will be 11448

________________________________________

Let see of if sum of digits of aa448 is divisible by  27

a+a+4+4+8 = 27

2a  = 27 - 16

2a = 11 = 2

a =11/2 = 5.5

as digit cannot be fraction of decimal, it can take value from 1 to 9 hence

sum of digits of aa448 is not divisible by  27

______________________________________________

Let see of if sum of digits of aa448 is divisible by  36

a+a+4+4+8 = 36

2a + 16 = 36

2a = 36-16 = 20

a =20/2 = 10

as digit can take value from 1 to 9 hence sum of digits of aa448 cannot  be divisible by  36 or any higher number than 36 which is divisible by 9.

Thus , a represent 1

and number is 11448.

5 0
2 years ago
to cover her rectangular screened porch with outdoor carpet, kendra needs at least 67.1 square feet of carpet. the length of ken
mixer [17]
I believe the answer is x is greater or equal to 54.9 (x=width)
4 0
2 years ago
In constructing a 95 percent confidence interval, if you increase n to 4n, the width of your confidence interval will (assuming
Damm [24]

Answer:

about 50 percent of its former width.

Step-by-step explanation:

Let's assume that our parameter of interest is given by \theta and in order to construct a confidence interval we can use the following formula:

\hat \theta \pm ME(\hat \theta)

Where \hat \theta is an estimator for the parameter of interest and the margin of error is defined usually if the distribution for the parameter is normal as:

ME = z_{\alpha} SE

Where z_{\alpha/2} is a quantile from the normal standard distribution that accumulates \alpha/2 of the area on each tail of the distribution. And SE represent the standard error for the parameter.

If our parameter of interest is the population proportion the standard of error is given by:

SE= \frac{\hat p (1-\hat p)}{n}

And if our parameter of interest is the sample mean the standard error is given by:

SE = \frac{s}{\sqrt{n}}

As we can see the standard error for both cases assuming that the other things remain the same are function of n the sample size and we can write this as:

SE = f(n)

And since the margin of error is a multiple of the standard error we have that ME = f(n)

Now if we find the width for a confidence interval we got this:

Width = \hat \theta + ME(\hat \theta) -[\hat \theta -ME(\hat \theta)]

Width = 2 ME (\hat \theta)

And we can express this as:

Width =2 f(n)

And we can define the function f(n) = \frac{1}{\sqrt{n}} since as we can see the margin of error and the standard error are function of the inverse square root of n. So then we have this:

Width_i= 2 \frac{1}{\sqrt{n}}

The subscript i is in order to say that is with the sample size n

If we increase the sample size from n to 4n now our width is:

Width_f = 2 \frac{1}{\sqrt{4n}} =2 \frac{1}{\sqrt{4}\sqrt{n}} =\frac{2}{2} \frac{1}{\sqrt{n}} =\frac{1}{\sqrt{n}} =\frac{1}{2} Width_i

The subscript f is in order to say that is the width for the sample size 4n.

So then as we can see the width for the sample size of 4n is the half of the wisth for the width obtained with the sample size of n. So then the best option for this case is:

about 50 percent of its former width.

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Leah claims the data in the table contains a cluster. why is leah’s statement true
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Answer:

c

Step-by-step explanation:

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2 years ago
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