Answer:
range is between 55.5 to 64.5
Step-by-step explanation:
Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches
68% is 1 standard deviation from mean
To get the range of 1 standard deviation we add and subtract standard deviation from mean
mean = 60
standard deviation = 4.5
60 - 4.5= 55.5
60+4.5 = 64.5
1 standard deviation is between 55.5 to 64.5
That is 68% range is between 55.5 to 64.5
Answer:
Washing cars= 4 hours
Walking dogs= 10 hours
Step-by-step explanation:
You want to start by creating equations. So one thing we know is that he makes $9 an hour washing cars(x) and $8 walking dogs(y).
$9x+$8y=$116
The second Equation is based off of the hours worked. We know that he worked 6 hours more walking the dogs than he did washing cars, so we can take x(being the washing hours) and add 6 to it to equal y (the number of dog hours).
y=x+6
Now You plug what y equals into the first equation to solve for x.
9x+8(x+6)=116 Next distribute the 8 to each term.
9x+8(x)+8(6)=116
9x+8x+48=116 Add the like terms together (9x+8x)
17x+48=116 Subtract the 48 from both sides
-48 -48
17x=68 Now divide by 17 on both sides.
______
17 17
x=4 Finally we can take x and plug it back in to one of the equations in order to solve for y. I'm going to choose the second equation.
y=(4)+6
y=10
Given that the<span> iq scores for large populations are centered at 100.
To get what percent of these 78 students have scores above 100 we conduct a normal distribution probability of the data.
P(x > 100) = P(z > (100 - 100)/sd) = P(z > 0) = 1 - P(z < 0) = 1 - 0.5 = 0.5 = 50%
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A. The mean and standard deviation.
The mean of a sampling distribution is approximately equal to the mean of the population. Given that the mean of the population is equal to 174.5, the mean of the sampling distribution is also this value.
The standard deviation of a sample distribution is equal to,
u(m) = u/sqrt n
Substituting the known values,
u(m) = 6.9 / sqrt 25 = 1.38
b. Get the z-score of both items,
z-score = (data point - mean) / standard deviation
z-score of 172.5
z-score = (172.5 - 174.5) / 1.38 = -1.49
This translates to 0.068.
z-score of 175.8
z-score = (175.8 - 174.5) / 1.38 = 0.94
This translates to 0.83.
The difference between the two z-scores is 0.762.
The number of samples with this height is 0.762(200) which is equal to approximately 152.
c. z-score of 172 centimeters
z-score = (172 - 174.5) / 1.38
z-score = -1.81
This translates to 0.03.
The number of people with this height from the sample is (0.03)(200) = 6
Answer:
The answer is explained below
Step-by-step explanation:
STEP 1
Out of 1500 units produced by a company 1,477 are found to be free of a particular type of defect. One needs to rate the performance based on Six Sigma Theory.
STEP 2
Manager can define the performance of a product using defects per million units DPMO metric
DPMO can be find by using
DPMO = Total number of defects in a sample/ No. of opportunities of per error per unit x No. of units * 1,000,000
= 1500 - 1477/ 1 x 1500* 1,000,000
= 23/1500
= 15,333,33
The defect rate of the process can be find by
Defect rate = No. of defects/ No. of units * 100
= 1500 - 1477/1500 * 100
= 23/1500 * 100
= 1.53%
Six Sigma theory focuses on achieving 3.4 defects per million for a certain period of time. However in this, performance of the process is not as good as stated by the manager.
