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Svetach [21]
2 years ago
7

Dylan has a total of 25 marbles. He gives 5 marbles to his sister, Jane. What

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
4 0
1/5th of the marbles
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The results of a mathematics placement exam at two different campuses of Mercy College follow: Campus Sample Size Sample Mean Po
Leona [35]

Answer:

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

Step-by-step explanation:

Data given

Campus   Sample size     Mean    Population deviation

   1                 330               33                      8

   2                310                31                       7

\bar X_{1}=33 represent the mean for sample 1  

\bar X_{2}=31 represent the mean for sample 2  

\sigma_{1}=8 represent the population standard deviation for 1  

\sigma_{2}=7 represent the population standard deviation for 2  

n_{1}=330 sample size for the group 1  

n_{2}=310 sample size for the group 2  

\alpha Significance level provided  

z would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for Campus 1 is higher than the mean for Campus 2, the system of hypothesis would be:

Null hypothesis:\mu_{1}-\mu_{2}\leq 0  

Alternative hypothesis:\mu_{1} - \mu_{2}> 0  

We have the population standard deviation's, and the sample sizes are large enough we can apply a z test to compare means, and the statistic is given by:  

z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

With the info given we can replace in formula (1) like this:  

z=\frac{(33-31)-0}{\sqrt{\frac{8^2}{330}+\frac{7^2}{310}}}}=3.37  

P value  

Since is a one right tailed test the p value would be:  

p_v =P(Z>3.37)=1-P(Z  

Comparing the p value with a significance level for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can say that the mean for the Campus 1 is significantly higher than the mean for the group 2.  

5 0
2 years ago
Let f: double-struck R4 → double-struck R and c(t): double-struck R → double-struck R4. Suppose ∇f(1, 1, π, e6) = (0, 1, 5, −2),
nalin [4]

d ( f o c) / dt = 9

( solution is attached below)

7 0
2 years ago
Ramon wants to plant cucumbers and tomatoes in his garden. He has room for
yarga [219]

Answer:

Number of Cucumbers = 12

Number of Tomatoes = 4

Step-by-step explanation:

Let number of cucumber be c and number of tomatoes be t

Since he has room for 16 plants, we can write:

c + t = 16

He wants to plant 3 times as many cucumbers as tomatoes. We can write:

c = 3t

We can substitute this in 1st equation and solve for t:

c + t = 16

3t + t = 16

4t = 16

t = 16/4 = 4

And c = 3t

c = 3(4) = 12

Number of Cucumbers = 12

Number of Tomatoes = 4

6 0
2 years ago
Read 2 more answers
mark has a cabinet door in his kitchen with the dimensions shown below. he creates a scale drawing where the width of the cabine
laiz [17]

Answer:

h^{*} = 25\,in

Step-by-step explanation:

Let consider that door has a height of 5 feet and a width of 3 feet. The scale factor is:

n = \frac{15\,in}{3\,ft}

n = 5\,\frac{in}{ft}

The height of the cabinet is:

h^{*} = n \cdot h_{door}

h_{*} = \left(5\,\frac{in}{ft}  \right)\cdot (5\,ft)

h^{*} = 25\,in

6 0
2 years ago
Read 2 more answers
What number comes next 16, 06, 68, 88,
inessss [21]

So the given series is "16, 06, 68, 88, __"

Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it(the one in 6), similarly in 06 it is two(one in zero and one in 6), going ahead, in 68 it is 3(one in 6 and two in 8).

From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.

Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.

4 0
2 years ago
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