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maks197457 [2]
2 years ago
13

Relative to the graph of y=3sinx what is the shift of the graph of y=3sin(x+pi/3)

Mathematics
1 answer:
DochEvi [55]2 years ago
4 0
The shifts of the sinus function can be described with the formula:
<span>a<span>sin<span>(<span><span>bx</span><span>−c</span></span>)</span></span></span>+<span>d, where
a is the amplitude
b is  the period
c is the phase shift 
d is the vertical shift
So, the graph y=3sinx is phase shifted. The phase shift can be calculated as c/b= pi/3/1=pi/3
So, the function is phase shifted for pi/3.</span>
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Which shows two triangles that are congruent by ASA
Ksenya-84 [330]
The four options are attached below

<u><em>Answer:</em></u>
Second attachment is the correct choice

<u><em>Explanation:</em></u>
ASA (angle-side-angle) means that two angles and the included side between them in the first triangle are congruent to the corresponding two angles and the included side between them in the second triangle

<u>Now, let's check the choices:</u>
<u>First attachment:</u>
It shows that two sides and the included angle between them in the first triangle is congruent to the corresponding two sides and the included angle between them in the second one. This is congruency by SAS. Therefore, this option is incorrect

<u>Second attachment:</u>
It shows that two angles and the included side  between them in the first triangle is congruent to the corresponding two sides and the included angle between them in the second triangle. This is congruency by ASA. Therefore, this option is correct

<u>Third attachment:</u>
It shows that the three angles in the first triangle are congruent to the corresponding three angles in the second one. This is not enough to prove congruency. Therefore, this option is incorrect

<u>Fourth attachment:</u>
It shows that the three sides in the first triangle are congruent to the corresponding three sides in the second one. This is congruency by SSS. Therefore, this option is incorrect.

Based on the above, the second attachment is the only correct one

Hope this helps :)

7 0
2 years ago
Read 2 more answers
Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}

Dividing we get,

2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}

Adding, we have,

2 { h } 54 \text { min }=2.9 {h}

Thus, the total time taken by Joshua is 2.9 {h}

To determine the average speed we use the formula,

speed=\frac{distance}{time}

where distance=7250 and time=2.9

Hence, substituting the values we have,

speed=\frac{7250}{2.9}

Dividing, we get,

speed=2500

Thus, the average speed of Joshua during that time is 2500 m/h.

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2 years ago
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G(x)=8(x2-6x)-5 its positive and it goes down.

5 0
2 years ago
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Solving radical equations<br> How to solve radical equations
Dafna1 [17]
Simplify radical expressions. If we combine these two things then we get the product property of radicals and the quotient property of radicals. These two properties tell us that the square root of a product equals the product of the square roots of the factors. no radicals appear in the denominator of a fraction.
8 0
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Kelly and Greta are asked to write an equation for the scenario below. “One person was able to plant 4 trees in the same amount
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<u>Answer:</u> Greta is correct.

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but you should follow a certain pattern to increase the value of x, such that every foe every value of x, one person is able to plant 4 trees.

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