Question

A spinner contains four sections: red, blue, green, and yellow. Joaquin spins the spinner twice. The set of outcomes is given as S = {RB, RG, RY, RR, BR, BG, BY, BB, GR, GB, GY, GG, YR, YB, YG, YY}. If the random variable is “yellow (Y),” which of the following is the correct probability distribution?
  

Answer 1

Answer:

Answer on edge is A :)

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

Given that  spinner contains four sections: red, blue, green, and yellow. Joaquin spins the spinner twice. The set of outcomes is given as

S = {RB, RG, RY, RR, BR, BG, BY, BB, GR, GB, GY, GG, YR, YB, YG, YY}.

If the random variable is “yellow (Y),” let us first find the values that Y can take.

From the sample space given above, we find that Y can take only 3 values 0,1,2

In the sample space of 16 entries, Y occurs 0 times in 9 times

1 time in 6 times and 2 times 1 time

Hence probability = no of favouable outcomes/number in sample space

So

P(Y=0) = 9/16

P(Y=1) = 6/16 = 3/8

P(Y=2) = 1/16