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Llana [10]
1 year ago
10

An ice-hockey puck is slid along ice in a straight line. The puck travels at a steady speed of 20 ms^-1 and experiences no frict

ional force. How far does the puck travel in 2.5 s?
a. 5 m
b. 8 m
c. 25 m
d. 50 m
Mathematics
1 answer:
laila [671]1 year ago
7 0

Answer:

d. 50 m

Step-by-step explanation:

1. You have the following information given in the problem above:

- The speed of the puck is 20 \frac{m}{s} and experiences no frictional force.

- The time is 2.5 seconds.

2. Then, to calculate the distance, you must apply the following formula:

d=Vt

Where d is the distance, V is the speed and t is the time.

3. Now, you must substitute values into the formula, as below:

d=(20\frac{m}{s})(2.5s)

4. Therefore, the result is:

d=50m


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\mu_{\bar x} = \mu = E(X) =30KWh

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

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