Question

An ice-hockey puck is slid along ice in a straight line. The puck travels at a steady speed of 20 ms^-1 and experiences no frictional force. How far does the puck travel in 2.5 s?
a. 5 m
b. 8 m
c. 25 m
d. 50 m

Answer 1

Answer:

d. 50 m

Step-by-step explanation:

1. You have the following information given in the problem above:

- The speed of the puck is 20 $\frac{m}{s}$ and experiences no frictional force.

- The time is 2.5 seconds.

2. Then, to calculate the distance, you must apply the following formula:

$d=Vt$

Where $d$ is the distance, $V$ is the speed and $t$ is the time.

3. Now, you must substitute values into the formula, as below:

$d=(20\frac{m}{s})(2.5s)$

4. Therefore, the result is:

$d=50m$