1)
.
2)
.
3) The particle is moving right when the velocity function is positive:
or
.
4) When
the particle is slowing down because the acceleration is close to zero
the particle is speeding up when acceleration is increasing away from zero:
.
5)
.
Answer:
a. 5 + 2i, 13 + 2i, 29 + 2i
Step-by-step explanation:
We'll use the formula f(z) = 2z + (3 - 2i) for each iteration. The output of the first iteration will be come the input of the second iteration, and so on.
So, we start with z0 = 1 + 2i and we plug that into the base equation:
z0 = 1 + 2i ==> f(z) = 2(1 + 2i) + 3 - 2i = 2 + 4i + 3 - 2i = 5 + 2i
z1 = 5 + 2i ==> f(z) = 2(5 + 2i) + 3 - 2i = 10 + 4i + 3 - 2i = 13 + 2i
z2 = 13 + 2i ==> f(z) = 2(13 + 2i) + 3 - 2i = 26 + 4i + 3 - 2i = 29 + 2i
z3 = 29 + 2i
Answer:
Step-by-step explanation:
A motorcycle has an initial speed of u m/s. It accelerates to a speed of 1.2u in 10 seconds
V = U + at
1.2u = u + a*10
=> a = 0.02u
S= ut + (1/2)at²
Distance in 1st 10 secs
S = u(10) + (1/2)(0.02)(10)²
=> S = 10u + u
=> S = 11u m
Constant speed 1.2u for 15 secs
S = 1.2u * 15
=> S = 18u m
Total Distance Covered d = 11u + 18u = 29u m
The end of the ray stops the x values from proceeding left at x=0. So your domain is from that point on to infinity. In your solution set x >= 0, since the arrow continues on the right side where x's are positive.
I assume his account balance will become negative. With no overdraft fees in the question, then his account balance should be $-12.
