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Aloiza [94]
2 years ago
10

Tom has $10 that he wants to use to buy pens and pencils. However, he does not want to buy more pens than pencils. A pen costs $

3, and a pencil costs $1. Which graph represents this scenario? (Here, x represents the number of pens and y the number of pencils.)
Mathematics
2 answers:
soldier1979 [14.2K]2 years ago
6 0
If he buys x pens and y pencils

 3x + y = 10
x ≤ y

You draw the line 3x + y = 10 .<span>(it passes by (0,10) and (-10/3,0)

</span>
<span>You Draw the line y=x [it passes by (0,0), (1,1), (2,2)]

 </span>
<span>Solution: is the points with integer x and y, that belong to the segment of the line 3x +y = 10 between the x-axis and the line y=x. Those points are (1,7) , (2,4), (3, 1).
</span>
 Hope this helps ^-^


marusya05 [52]2 years ago
3 0
Hello!

We 1st off, know that number of pencils = x

and that the number of pens = y

So now the Solving!:

3x + y = 10
x ≤ y

Draw the line 3x + y = 10 .[it passes by (0,10) and (-10/3,0)

Draw the line y=x [it passes by (0,0), (1,1), (2,2) etc]

Then the solution is the points with integer x and y, that belong to the segment of the line 3x +y = 10 between the x-axis and the line y=x. Those points are (1,7) , (2,4), (3, 1).


I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! And MARK AS BRAINLIEST IF HELPED! :)
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He lost 147.35 marks

Step-by-step explanation:

Take the total marks and subtract the marks he got to find the marks he lost

600-452.65= 147.35

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Acute. No triangle can have more than 1 obtuse angle.

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A given set of values is found to be a normal distribution with a mean of 140 and a standard deviation of 18.0. Find the value t
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Answer:

The value that is greater than 45% of the data values is approximately 137.84.

Step-by-step explanation:

The key is transforming values from this distribution to a z-score range and finding the corresponding value using a z-score table.

We are looking for a value x which attains a critical z-score that corresponds to the (100-45)%=55-th percentile:

z_{0.55} = \frac{x-\mu}{\sigma}=\frac{x-140}{18}\implies x = 18\cdot z_{0.55}+140

The critical z value (from z-score table, online) is: -0.12, so:

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The value that is greater than 45% of the data values is approximately 137.84.


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Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

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No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

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School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

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For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

IQR=Q_3-Q_1=15.5-8=7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

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