answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
White raven [17]
2 years ago
15

The following table shows the number of hours some teachers in two schools expect students to spend on homework each week: Schoo

l A 9 14 15 17 17 7 15 6 6 School B 12 8 13 11 19 15 16 5 8 Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (6 points) Part B: Are the box plots symmetric? Justify your answer. (4 points)
Mathematics
1 answer:
Lerok [7]2 years ago
4 0

Answer:

For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5

For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5

No, the box plots are not symmetric.

Step-by-step explanation:

Part A

The given data sets are

School A : 9,14,15,17,17,7,15,6,6

School B : 12,8,13,11,19,15,16,5,8

Arrange the data in ascending order.

School A : 6,6,7,9,14,15,15,17,17

School B : 5,8,8,11,12,13,15,16,19

Divide each data set in four equal parts.

School A : (6,6),(7,9),14,(15,15),(17,17)

School B : (5,8),(8,11),12,(13,15),(16,19)

For school A:

Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17

Interquartile range of the data is

IQR=Q_3-Q_1=16-6.5=9.5

For school B:

Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19

Interquartile range of the data is

IQR=Q_3-Q_1=15.5-8=7.5

Part B:

The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.

Guest
1 year ago
what are the outliers
You might be interested in
A circle passes through points A(7,4), B(10,6), C(12,3). Show that AC must be the diameter of the circle.
Artist 52 [7]

so we have three points, A, B and C, if indeed AC is the diameter of the circle, then half the distance of AC is its radius, and the midpoint of AC is the center of the circle, morever, since B is also on the circle, the distance from B to the center must be the same radius distance.

in short, half the distance of AC must be equals to the distance of B to the midpoint of AC, if indeed AC is the diameter.

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{12}~,~\stackrel{y_2}{3}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{12+7}{2}~~,~~\cfrac{3+4}{2} \right)\implies \left( \cfrac{19}{2}~~,~~\cfrac{7}{2} \right)=M\impliedby \textit{center of the circle}

now, let's check the distance from say A to the center, and check the distance of B to the center, if it's indeed the center, they'll be the same and thus AC its diameter.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ A(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ AM=\sqrt{\left( \frac{19}{2}-7 \right)^2+\left( \frac{7}{2}-4 \right)^2} \\\\\\ AM=\sqrt{\left( \frac{5}{2}\right)^2+\left( -\frac{1}{2} \right)^2}\implies \boxed{AM\approx 2.549509756796392} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{10}~,~\stackrel{y_1}{6})\qquad M(\stackrel{x_2}{\frac{19}{2}}~,~\stackrel{y_2}{\frac{7}{2}}) \\\\\\ BM=\sqrt{\left( \frac{19}{2}-10 \right)^2+\left( \frac{7}{2}-6 \right)^2} \\\\\\ BM=\sqrt{\left( -\frac{1}{2}\right)^2+\left( -\frac{5}{2} \right)^2}\implies \boxed{BM\approx 2.549509756796392}

6 0
2 years ago
Which equation shows the point-slope form of the line that passes through (3, 2) and has a slope of y plus StartFraction one-hal
vesna_86 [32]

Answer:

B. y - 2 = 1/3(x - 3)

4 0
2 years ago
Read 2 more answers
What expressions are equivalent to-2(2h + 10) ×4h ​
Feliz [49]

Answer: 16x^2 - 80x

if you simplify

Step-by-step explanation:

<em>hope this helps pls mark brainliest</em>

7 0
2 years ago
If cyanide in a stream next to a gold mine increases from 240 ppm to 360 ppm, what percent increase is this?
avanturin [10]

Given :

Initial concentration , 240 ppm .

Final concentration , 360 ppm .

To Find :

Percent increase.

Solution :

Percentage increase is given by :

=\dfrac{Final-Initial}{Initial}\times 100\\\\=\dfrac{360-240}{240}\times 100\\\\=50\%

Therefore , percent increase is 50 % .

Hence , this is the required solution .

4 0
2 years ago
Given that 1 inch = 2.54 cm, 1 cm3 is equal to
Mashutka [201]
<span>We know that 1 cm3 is 1 cm * 1 cm * 1 cm, so in inches: 1 cm3 = 1 inch3/2.54^3 cm3 = 1/2.54*1/2.54*1/2.54 = 1/16.387 = 0.061 inch3 Another way to solve is: 1 inch = 1 inch/2.54 cm = 0.3937 cm Then 1 inch3 = 0.3937^3 cm = 0.061 inch3</span>
7 0
2 years ago
Other questions:
  • A while back, either James borrowed $12 from his friend Rita or she borrowed $12 from him, but he can’t quite remember which. Ei
    14·1 answer
  • Quadrilaterals WXYZ and BADC are congruent. In addition, WX ≅ DC and XY ≅ BC. If AD = 4 cm and AB = 6 cm, what is the perimeter
    6·2 answers
  • Hillary rolls 2 number cubes numbered 1 through 6 while playing her favorite board game. She will get a second turn if she rolls
    15·2 answers
  • Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
    13·1 answer
  • A pizza is cut into six unequal slices (each cut starts at the center). The largest slice measures $90$ degrees: [asy] unitsize(
    5·1 answer
  • Statistical Process Control (SPC) is often described as an applied side of the Binomial, Poisson, and Normal distributions. Many
    6·1 answer
  • The figure shows a square floor plan with a smaller square area that will accommodate a combination fountain and pool.The floor
    11·1 answer
  • If the end behavior is increasing to the left, what might be true about the function? Select all that apply.
    6·1 answer
  • In​ 2004, an art collector paid ​$ for a particular painting. The same painting sold for ​$ in 1950. Complete parts​ (a) through
    12·1 answer
  • Find the area of the shape below.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!