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zmey [24]
2 years ago
9

American households spent an average of about $52 in 2007 on Halloween merchandise such as costumes, decorations and candy. To s

ee if this number had changed, researchers conducted a new survey in 2008 before industry numbers were reported. The survey included 1,500 households and found that average Halloween spending was $58 per household.The sample mean is __________ dollars, while the claimed population mean is _________ dollars.
Mathematics
1 answer:
Grace [21]2 years ago
6 0

Answer:

The sample mean is$ 52

The claimed population mean is $58

Step-by-step explanation:

American households spent an average of about $52 in 2007 on Halloween merchandise such as costumes, decorations and candy. This tells you that the sample mean is$ 52.

1500 households were surveyed in 2008 and found an average spending of $58 0n Halloween tell us that the claim's population mean is $58

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To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assig
Keith_Richards [23]

Answer:

1. Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C

2. D. 36

3. C. 34

4. B. 1.059

5. B. 8.02

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Part 1

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C

Part 2

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2

And we have this property

SST=SS_{between}+SS_{within}

We need to find the mean for each group first and the grand mean.

\bar X =\frac{\sum_{i=1}^n x_i}{n}

If we apply the before formula we can find the mean for each group

\bar X_A = 27, \bar X_B = 24, \bar X_C = 30. And the grand mean \bar X = 27

Now we can find the sum of squares between:

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2

Each group have a sample size of 4 so then n_j =4

SS_{between}=SS_{model}=4(27-27)^2 +4(24-27)^2 +4(30-27)^2=72

The degrees of freedom for the variation Between is given by df_{between}=k-1=3-1=2, Where  k the number of groups k=3.

Now we can find the mean square between treatments (MSTR) we just need to use this formula:

MSTR=\frac{SS_{between}}{k-1}=\frac{72}{2}=36

D. 36

Part 3

For the mean square within treatments value first we need to find the sum of squares within and the degrees of freedom.

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2

SS_{error}=(20-27)^2 +(30-27)^2 +(25-27)^2 +(33-27)^2 +(22-24)^2 +(26-24)^2 +(20-24)^2 +(28-24)^2 +(40-30)^2 +(30-30)^2 +(28-30)^2 +(22-30)^2 =306

And the degrees of freedom are given by:

df_{within}=N-k =3*4 -3 = 12-3=9. N represent the total number of individuals we have 3 groups each one with a size of 4 individuals. And k the number of groups k=3.

And now we can find the mean square within treatments:

MSE=\frac{SS_{within}}{N-k}=\frac{306}{9}=34

C. 34

Part 4

The test statistic F is given by this formula:

F=\frac{MSTR}{MSE}=\frac{36}{34}=1.059

B. 1.059

Part 5

The critical value is from a F distribution with degrees of freedom in the numerator of 2 and on the denominator of 9 such that we have 0.01 of the area in the distribution on the right.

And we can use excel to find this critical value with this function:

"=F.INV(1-0.01,2,9)"

And we will see that the critical value is F_{crit}=8.02

B. 8.02

5 0
2 years ago
Write an expression using the distributive property to find the product of 7×63
alekssr [168]
(7x6) + (7x3) = c. this is the answer
5 0
2 years ago
URGENTTT PLEASE ANSWER QUICKLY!!!!!!!!!!!!!!!!!!!!
klio [65]

Mine said it was a triangle

8 0
2 years ago
Read 2 more answers
A 63 liter mixture contains milk and water in a ratio of 4:5. then x liters of milk and y liters of water are added to the mixtu
KatRina [158]

Answer:

X+y=237Litres

Step-by-step explanation:

Let a be mixture of milk and water.

Let x =milk

Let y= water

z = x+y

Final volume of mixture =63litres + z

5/12(3+z))+60=8/15(63-z)

z =x+y= 237litres

4 0
2 years ago
The probability distribution of the number of loaves of bread sold in a bakery in a week based on past data is given below. Iden
Tpy6a [65]

Answer:

E(X) = 100*0.25+ 148*0.36 + 135*0.21 + 200*0.18 = 142.63

And for this case the expected value for this random variable is given by 142.63 and rounded to the nearest integer we got 143. And that  represent the number of loaves of bread sold for one week

Step-by-step explanation:

For this case we have the following distirbution given:

X:      100   148   135   200

P(X): 0.25 0.36   0.21  0.18

The expected value is given by:

E(X) = \sum_{i=1}^n X_i P(X_i)

And replacing we got:

E(X) = 100*0.25+ 148*0.36 + 135*0.21 + 200*0.18 = 142.63

And for this case the expected value for this random variable is given by 142.63 and rounded to the nearest integer we got 143. And that  represent the number of loaves of bread sold for one week

4 0
2 years ago
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