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Ainat [17]
2 years ago
8

Mr. Torres took his students to the dolphin show. Each row in the stadium had 11 seats. One adult sat at each end of a row, and

each group of 4 students was seated between 2 adults. Mr. Torres sat by himself. How many adults were there?
Mathematics
1 answer:
Katena32 [7]2 years ago
3 0

Answer:

3

Step-by-step explanation:

The given data shows that only 1 row was in use. We also know that Mr. Torres is an adult. So for the ease, lets use A for Adult and S for student.

The seating must fulfill the requirements that 4 students must be between adults such that it would be "A-S-S-S-S-A"

On a row of 11 seats, this should be the searing arrangements.

A-S-S-S-S-A-S-S-S-S-A ( for 1 row).

Mr. Torres could be any A .

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What percent of 20 is 30
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   30 x ( 20 / 100 )
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Two-digit natural numbers are formed, with replacement, from the digits 0 through 9.
alexdok [17]

Answer:

The first digit of a two digit number can be any of digits 1 - 9. It cannot be 0 though. Therefore there are 9 possible digits for the first place.

There are 5 possible digits for the second position. The two digit number has to be odd and therefore the final digit must be 1,3,5,7 or 9

Therefore for each and every one of the nine first digits there are 5 digits that the second can be.

Therefore ANSWER = 9 * 5 = 45 possible permutations.

2. The largest two digit number = 99

Subtract 57 and you get 42

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The forty two numbers are 58 ,59, 60, 61......98, 99

7 0
2 years ago
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Crackers come in packages of 24. Cheese slices come in packages of 18. Andy wants one cheese slice for each cracker. Patrick mad
ANEK [815]

Patrick's statement is incorrect.

Explanation:

Crackers come in package of = 24

Cheese slices come in package of = 18

As given, Andy wants one cheese slice for each cracker so we will find the least common multiple of 24 and 18.

The L.C.M is 72.

So, Andy needs 72 crackers and 72 cheese slices.

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4 0
1 year ago
Eighty members of a bike club were asked whether they like touring bikes and whether they like mountain bikes. A total of 70 lik
blondinia [14]

Answer: Choice B

a = 42, b = 5, c = 28, d = 33, e = 10

====================================================

Explanation:

Refer to the diagram below. We have a table of values in which some values (if not most) are unknown. We have variables as placeholders until we can figure out which numbers replace them.

Along the bottom row, we see that 70+e = 80, which solves to e = 10. I subtracted 70 from both sides.

That must mean the answer is between choice A or choice B.

--------------------------

Since e = 10, and b+5 = e (third column), we can replace the 'e' with 10 to get the equation b+5 = 10. That solves to b = 5. This rules out choice A.

The final answer is choice B

---------------------------

If you want to keep going to find a, c and d, then let's solve a+b = 47 which is the same as a+5 = 47 after replacing letter b with 5.

a+5 = 47 solves to a = 42 after subtracting both sides by 5.

Then along the first column, we see that a+c = 70 which is the same as 42+c = 70. Isolating c gets us c = 28

Lastly, c+5 = d is shown along the second row. Plug in c = 28 to find that d = c+5 = 28+5 = 33

So overall we have:

a = 42, b = 5, c = 28, d = 33, e = 10

7 0
2 years ago
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