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2 years ago

1)Given: AB = 4 AD = 6

Mathematics

1 answer:

Vaselesa [24]2 years ago

5 0

1)Given: AB = 4 AD = 6
What is the name of the radius of the larger circle?
the answer part 1) is
the radius of the larger circle is AD

2)Given: AB = 4 AD = 6
What point is in the interior of both circles?
the answer Part 2) is
The point A (the center of the circles)

3) Given: AB = 4 AD = 6
Which points are in the exterior of both circles?
the answer Part 3) is
E and G

4)The circles are _____.
the answer Part 4) is
concentric

5)If AC = 20 and BD = 8, what is the radius of the smaller circle?
we know that
radius smaller circle=AB
and
AB=AC-BD--------> AC=20-12-------> AC=8 units

the answer part 5) is
the radius of the smaller circle is 12 units

6)Given: AB = 4 AD= 6
What is the length of BD?
we know that
AD=AB+BD
solve for BD
BD=AD-AB--------> BD=6-4-----> BD=2 units

the answer Part 6) is
the length of BD is 2

7)Given: AB = 4 AD = 6
What is the name of the radius of the smaller circle?

the answer Part 7) is
the name of the radius of the smaller circle is AB

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Solution:

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Now, we have to find how many cookies can each person p will get.

Let, the total number of persons be x.

Then, after equally sharing the cookies,

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Answer:

The probability that all three have type B+ blood is 0.001728

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a person in the United States has type B+ blood is 12%.

This means that $p = 0.12$

Three unrelated people in the United States are selected at random.

This means that $n = 3$

Find the probability that all three have type B+ blood.

This is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{3,3}.(0.12)^{3}.(0.88)^{0} = 0.001728$

The probability that all three have type B+ blood is 0.001728

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Well you are look at a 3d image here
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11/3 on the calculator is 3.66666667 sooooo....
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side 2: 3 x 6 = 18
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now we just add them up together.
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