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Ostrovityanka [42]
2 years ago
5

Shorty’s Muffler advertises it can install a new muffler in 30 minutes or less. However, the work standards department at corpor

ate headquarters recently conducted a study and found that 20% of the mufflers were not installed in 30 minutes or less. The Maumee branch installed 50 mufflers last month. If the corporate report is correct: How many of the installations at the Maumee branch would you expect to take more than 30 minutes?
Mathematics
1 answer:
pav-90 [236]2 years ago
7 0

Answer:

The installations at the Maumee branch would you expect to take more than 30 minutes is 10.

Step-by-step explanation:

Consider the provided information.

Let x is the installations at the Maumee branch take more than 30 minutes.

The work standards department at corporate headquarters recently conducted a study and found that 20% of the mufflers were not installed in 30 minutes or less.

Therefore, π=0.20

The Maumee branch installed 50 mufflers last month.

Thus, n=50

Mean of the distribution: μ=nπ

Substitute the respective values in the above formula.

μ=(50)(0.20)

μ=10

Hence, the installations at the Maumee branch would you expect to take more than 30 minutes is 10.

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Answer:

300

Step-by-step explanation:

Sum the parts of the ratio : 3 + 2 = 5 parts

Divide the number of appointments by 5 to find the value of one part of the ratio, that is

\frac{500}{5} = 100 ← value of 1 part of the ratio

The mums consisted of 3 parts, hence

3 × 100 = 300 ← appointments with mums

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2 years ago
A shipment of 7 television sets contains 2 defective sets. A hotel makes a random purchase of 3 of the sets. If x is the number
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Answer:

The probability distribution is

X    :        0              1                 2

f(X) :       2/7          4/7               1/7

Step-by-step explanation:

Let x is the number of defective sets purchased by the hotel.

Total number of television sets = 7

Total number of defective television sets = 2

Since there are 2 defective television sets and hotel purchase 3 sets, So, X=0,1,2.

If X=0,

P(X=0)=\frac{^5C_3}{^7C_3}=\frac{10}{35}=\frac{2}{7}

If X=1,

P(X=1)=\frac{^5C_2\cdot ^2C_1}{^7C_3}=\frac{10\cdot 2}{35}=\frac{4}{7}

If X=2,

P(X=2)=\frac{^5C_1\cdot ^2C_2}{^7C_3}=\frac{5\cdot 1}{35}=\frac{1}{7}

The probability distribution is

X    :        0              1                 2

f(X) :       2/7          4/7               1/7

The probability histogram is shown below.

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a table to summarize costs Sheri gives her dog groomer a generous tip. Using a benchmark fraction and the table, estimate the ti
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Your Answer Will Be 15$

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The erea of a square is given by x2, where x is the length of one side. Mary's original garden was in the shape of a square. She
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Answer: The expression that represents the area of Mary's new garden =2x^2

Step-by-step explanation:

The area of a square is given by x^2, where x is the length of one side. The length of the other side is also x. In a square, all sides are equal. each of the four sides equal x

Area = x × x

Area = x^2

She decided to double the area of her garden

New area = 2(x × x)

New area = 2x^2

The expression that represents the area of Mary's new garden =2x^2

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Estimates show that there are 1.4x10^8 pet fish and 9.4x10^6 pet reptiles in the United States. How many pet fish and reptile pe
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Answer:

There are total number of pet fish and reptile pets are 1.49\times 10^8.

Step-by-step explanation:

Number of pet fish are 1.4\times 10^8 and the number of pet reptiles are 9.4\times 10^6.

It is required to find the total number of pet fish and reptile pets in the United States. It can be done by simply adding the above numbers such that total numbers are given by :

T=1.4\times10^{8}+9.4\times10^{6}\\\\T=149400000\\\\T=1.49\times 10^8

So, there are total number of pet fish and reptile pets are 1.49\times 10^8.

8 0
2 years ago
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