X = 96
100 137.4
137.4x=(100)(96)
137.4x=9600
137.4x/137.4=9600/137.4
x=70%
Answer:
t = 137.9 years
Step-by-step explanation:
Hi, to answer this question we have to apply an exponential growth function:
A = P (1 + r) t
Where:
p = original population
r = growing rate (decimal form)
t= years
A = population after t years
Replacing with the values given:
A = 6,250 (1 + 3.75/100)^t
A = 6,250 (1 + 0.0375)^t
A = 6,250 (1.0375)^t
1915-1890 = 25 years passed (t)
A = 6,250 (1.0375)^25
A = 15,689
1940-1890 = 50 years passed (t)
A = 6,250 (1.0375)^50
A = 39,381
- When will the population reach 1,000,000?. We have to subtitute A=1000000 and solve for t.
1,000,000= 6,250 (1.0375)^t
1,000,000/ 6,250 =(1.0375)^t
160 = 1.0375^t
log 160 = log 1.0375^t
log 160 = (t ) log 1.0375
log160 / log 1.0375= t
t = 137.9 years
G= 48/4???? that would make sense wouldn't it? because 48/4 would be the total number of points divided by the amount of games in which those points are scored.
Answer:
1.5b (kg)
Step-by-step explanation:
Let's begin by listing out the variables we were given:
weight of the watermelon = b (kg),
weight of watermelon = (2/5) * weight of candies
weight of candies = 1 ÷ (2/5) = 1 ÷ 0.4
weight of candies = 2.5b (kg)
How much is the weight of the box of candies greater than the weight of the watermelon is given by:
weight of the box of candies - weight of watermelon= 2.5b - b = <u>1.5b</u> (kg)
<u>Therefore, the weight of the box of candies is greater than the weight of the watermelon by 1.5b (kg) </u>
