Jazmine needs $30,000 to pay off a loan at the end of 5 years. How much must she deposit monthly into

Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc

babunello [35]

For this case, the first thing we are going to do is write the generic equation of motion for the vertical axis.

We have then:

$h = \frac {1} {2} gt ^ 2 + vo * t + h0$

Where,

g: acceleration of gravity
vo: initial speed
h0: initial height

For the first body:

$h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21$

For the second body:

$h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50$

By the time both bodies have the same height we have:

$h1 = h2\\$

$\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50$

Rewriting we have:

$\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50$

$\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21$

$\frac {19} {12} * t = 29$

Clearing time:

$t = 29 (\frac {12} {19})\\t = 18.31s$

Answer:

it takes 18.31s for the two window washers to reach the same height

6 0

2 years ago

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The owner of a manufacturing plant employs eighty people. As part of their personnel file, she asked each one to record to the n

wariber [46]

Answer:

Mean of the sample = 27.83

The variance of the the sample = 106.96

Standard deviation of the sample = 10.34

Step-by-step explanation:

Step(i):-

Given random sample of six employees

x 26 32 29 16 45 19

mean of the sample

$x^{-} = \frac{26+32+29+16+45+19}{6} = 27.83$

Mean of the given data = 27.83

Step(ii):-

Given data

x : 26 32 29 16 45 19

x - x⁻ : -1.83 4.17 1.17 -11.83 17.17 -8.83

(x - x⁻)² : 3.3489 17.3889 1.3689 139.9489 294.80 77.9689

∑ (x-x⁻)² = 534.8245

Given sample size 'n' =6

The variance of given data

S² = ∑(x-x⁻)² / n-1

$S^{2} = \frac{534.8245}{6-1} = 106.9649$

The variance of the given sample = 106.9649

Step(iii):-

Standard deviation of the given data

$S = \sqrt{variance} = \sqrt{106.9649} =10.3423$

Standard deviation of the sample = 10.3423

8 0

2 years ago

What is the domain and range of the equation y=500(1.08)^x

Marina CMI [18]

(x) is an element of a real number. This means it could be an integer, fraction or irrational number.

* As x approaches infinity, y approaches infinity.

* As x approaches minus infinity, y approaches 0.

-------------

Domain:

(x) is an element of a real number

Range:

y>0

6 0

2 years ago

The distributive property can be applied to which expression to factor 12x3 – 9x2 4x – 3?

fomenos

3x2(4x – 3) + 1(4x – 3)

3 0

2 years ago

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A study was conducted to determine if there was a difference in the driving ability of students from West University and East Un

Sholpan [36]

Answer:

There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, assuming a significance level 0.1

Step-by-step explanation:

Let p1 be the proportion of West University students who involved in a car accident within the past year

Let p2 be the proportion of East University students who involved in a car accident within the past year

Then

$H_{0}:$ p1=p2

$H_{a}:$ p1≠p2

The formula for the test statistic is given as:

z= $\frac{p1-p2}{\sqrt{\frac{p*(1-p)*(n1+n2)}{n1*n2} } }$ where

p1 is the sample proportion of West University students who involved in a car accident within the past year (0.15)
p2 is the sample proportion of East University students who involved in a car accident within the past year (0.12)

p is the pool proportion of p1 and p2 ( $\frac{15+12}{100+100}=0.135$ )
n1 is the sample size of the students from West University (100)
n2 is the sample size ofthe students from East University (100)

Then we have z= $\frac{0.03}{\sqrt{\frac{0.135*0.865*(100+100)}{100*100} } }$ ≈ 0.6208

Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.

Assuming significance level 0.1, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance

6 0

1 year ago