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Fed [463]
2 years ago
5

Which facts could be applied to simplify this expression? Check all that apply.

Mathematics
2 answers:
Harlamova29_29 [7]2 years ago
4 0

Answer:

Options B, C, and D.

Step-by-step explanation:

We have to simplify the given expression given (5x + 3y + (-x) + 6z).

We will use the process as given below.

1) We will identify the like terms, we have to add or subtract.

2) Like terms are those, which have the same variable of the same degree.

3) We get the simplified expression by combining the same terms.

5x + 3y + (-x) + 6z = 4x + 3y + 6z

Therefore, Options B, C and D will be the correct options.

kykrilka [37]2 years ago
3 0

The answer is B, C, and D. Like terms are terms with all the same variable, so 5x and -x are like terms.

C is correct. If we add -x to 5x, we get 4x. The other numbers remain unchanged because they have no like terms.

D is correct. Applying the rule of like terms, which is that like terms are numbers with the same variable, only add together numbers with the same variable.

Hope this helps!

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Frank Fitness found a correlation coefficient of -0.74 between hours of strenuous exercise each week and a standard measure of b
Evgen [1.6K]

Answer:

b. strong; negative

Step-by-step explanation:

When a correlation has a value greater than 0.74 or lesser than -0.70, it is classified as a strong correlation.

A negative value for a correlation means a negative (downhill) linear correlation.

Therefore, since the correlation coefficient found by Frank Fitness is -0.74, there is a strong and negative relationship between hours of strenuous exercise and body mass.

8 0
2 years ago
rectangle abcd is similar to rectangle pqrs. given ab=14 cm, BC=8cm and pq=21cm, calculate the length of QR
weqwewe [10]
QR =12 because you set up a proportion 21/14=x/8 then cross multiply and get 14x=168 then you divide and get 12
6 0
2 years ago
What is 576 hundredths in decimal form
fiasKO [112]
5.76 because the hundredths place is two spaces to the right of the decimal point.
6 0
2 years ago
Suppose the area that can be painted using a single can of spray paint is slightly variable and follows a nearly normal distribu
Svetllana [295]

Answer:

Step-by-step explanation:

Hello!

You have the variable

X: Area that can be painted with a can of spray paint (feet²)

The variable has a normal distribution with mean μ= 25 feet² and standard deviation δ= 3 feet²

since the variable has a normal distribution, you have to convert it to standard normal distribution to be able to use the tabulated accumulated probabilities.

a.

P(X>27)

First step is to standardize the value of X using Z= (X-μ)/ δ ~N(0;1)

P(Z>(27-25)/3)

P(Z>0.67)

Now that you have the corresponding Z value you can look for it in the table, but since tha table has probabilities of P(Z, you have to do the following conervertion:

P(Z>0.67)= 1 - P(Z≤0.67)= 1 - 0.74857= 0.25143

b.

There was a sample of 20 cans taken and you need to calculate the probability of painting on average an area of 540 feet².

The sample mean has the same distribution as the variable it is ariginated from, but it's variability is affected by the sample size, so it has a normal distribution with parameners:

X[bar]~N(μ;δ²/n)

So the Z you have to use to standardize the value of the sample mean is Z=(X[bar]-μ)/(δ/√n)~N(0;1)

To paint 540 feet² using 20 cans you have to paint around 540/20= 27 feet² per can.

c.

P(X≤27) = P(Z≤(27-25)/(3/√20))= P(Z≤2.98)= 0.999

d.

No. If the distribution is skewed and not normal, you cannot use the normal distribution to calculate the probabilities. You could use the central limit theorem to approximate the sampling distribution to normal if the sample size was 30 or grater but this is not the case.

I hope it helps!

4 0
2 years ago
Kara starts tying a baby quilt at the local community center. Each quilt takes 200 ties to complete. Ten minutes later Julie joi
Tju [1.3M]

Answer:

a) K(t)=6\frac{tie}{min}(t)

b)J(t)=11\frac{tie}{min}(t)

c)T_{f}(t)=K(t+10)+J(t) where T_{f}(t)= number ties finished per unit time

d) t≅8.24min

e) K=109tie

   J=91tie

f) K≅16.6min

  J≅9.09min

Step-by-step explanation:

Data

Kara_{(K)}=6\frac{tie}{min}\\Julie(J)=11\frac{tie}{min}

Kara begins ten minutes before julie, so when julie joins kara she has 60 ties

t=10 k=6\frac{tie}{min}*10min=60tie

a) K(t)=6\frac{tie}{min}(t)

b)J(t)=11\frac{tie}{min}(t)

c)T_{f}(t)=K(t+10)+J(t) where T_{f}(t)= number ties finished per unit time

d) if kara already has 60 ties and makes 6 per minute and Julie makes 11 per minute then per minute they makes 17 ties, so one minute per 17 ties for 200 ties ¿how long?. t=\frac{(200-60)tie*min}{17tie}≅8.24min

e) K=60tie+6tie/min*8.24min=109tie

   J=11tie/min*8.24min=91tie

f) K=100tie*min/6tie≅16.6min

  J=100tie*min/11tie≅9.09min

Note: the amount of ties were rounded to the nearest decimal

6 0
2 years ago
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