Answer: HiiiIiI hi hi
Step-by-step explanation:
Hi hi hi
P.S thats what u did to me :)
It’s 5 divided by 6 bc the 5 is the numerator, no she is not correct.
Hi there!
PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)
Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1
PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.
Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
x = 4 strawberry wafers
4 + y = 22 (substituting x into the first equation to solve for y)
y = 18 chocolate wafers
ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
20 by 20
Step-by-step explanation:
the new dimensions have to be 12 because 12×12 =144 so you would add 8 to 12 and get 20 for each side
Answer:
Step-by-step explanation:
Total weight of all of the filled jars with jam = 211.2 ounces
When empty, each jar weighs 1.2 ounces
Total weight of 2 dozens of empty jar = 24 × 1.2 ounces
= 28.8 ounces
Total weight of jam in 2 dozens jar = Total weight of all of the filled jars with jam - Total weight of 2 dozens of empty jar
= 211.2 ounces - 28.8 ounces
= 182.4 ounces
The weight of jam in one jar = 182.4 ounces / 24 jars
= 7.6 ounces
The weight of jam in one jar = 7.6 ounces