Answer: $600,600
Step-by-step explanation:
Total handling cost :
Workpiece moved * cost * distance
Work area A :
-, (5 × 22 × 900), (9 × 22 × 900), (7 × 22 × 500)
-, 99000, 178200, 77000
Work area B:
-, -, (6 × 22 × 500), (8 × 22 × 200)
-, -, 66000, 35200
Work area C:
-, -, -, (11 × 22 × 600)
-,-,-, 145200
Work area D:
-, -, -, -
Total weekly handling cost :
(99000 + 178200 + 77000 + 66000 + 35200 + 145200)
= $600,600
Kindly check attached picture for more explanation
Answer:
7.5kilometer
Step-by-step explanation:
for 30mins semin runs 5kilometer
then for 1min: (1min×5kilometer)÷30mins,
therefore, for 45mins: (45mins×5kilometer)÷30mins=7.5kilometer
I think the answer would be 24 but im not 100% sure
<em>I believe what you need to do is multiply 3 by each number.
To start, 3*584 is 1752. Expanded form written out would be (3*500)+(3*80)+(3*4). Simply multiply all the numbers and then add them together. 3*500=1,500; 3*80=240; 3*4=12. 1,500+240=1740+12=1752. Hope this helps! :)</em>
angle AOB = 132 and is also the sum of angles AOD and
DOB. Hence
angle AOD + angle DOB = 132° ---> 1
angle COD = 141 and is also the sum of angles COB and BOD. Hence
angle COB + angle DOB = 141° ---> 2
Now we add the left sides together and the right sides of equations 1 and 2
together to form a new equation.
angle AOD + angle DOB + angle COB + angle DOB = 132 + 141 ---> 3
We should also note that:
angle AOD + angle DOB + angle COB = 180°
Therefore substituting angle AOD + angle DOB + angle COB in equation 3 by 180
and solving for angle DOB:
180 + angle DOB = 132 + 141
angle DOB = 273 - 180 = 93°