Answer:
- hexahedron: triangle or quadrilateral or pentagon
- icosahedron: quadrilateral or pentagon
Step-by-step explanation:
<u>Hexahedron</u>
A hexahedron has 6 faces. A <em>regular</em> hexahedron is a cube. 3 square faces meet at each vertex.
If the hexahedron is not regular, depending on how those faces are arranged, a slice near a vertex may intersect 3, 4, or 5 faces. The first attachment shows 3- and 4-edges meeting at a vertex. If those two vertices were merged, then there would be 5 edges meeting at the vertex of the resulting pentagonal pyramid.
A slice near a vertex may create a triangle, quadrilateral, or pentagon.
<u>Icosahedron</u>
An icosahedron has 20 faces. The faces of a <em>regular</em> icosahedron are all equilateral triangles. 5 triangles meet at each vertex.
If the icosahedron is not regular, depending on how the faces are arranged, a slice near the vertex may intersect from 3 to 19 faces.
A slice near a vertex may create a polygon of 3 to 19 sides..
Answer:
2^27
Step-by-step explanation:
Given the following expression:
[(2^10)^3 x (2^-10)] ÷ 2^-7
This can be easily simplified. Let us simplify the numerator first. To do that, we have
(2^10)^3 making use of the power rule of indices that says:
(A^a)^b = A^ab where a and b are powers, we have:
2^(10x3) = 2^30
Therefore the numerator becomes:
2^30 x 2^-10. Also making use of the multiplication rule that says:
A^a x A^b = A^(a + b), we have
2^30 x 2^-10 = 2^(30 – 10) = 2^20.
Now we have:
(2^20) ÷ (2^-7)
To simplify this, we need the division rule of indices which says:
A^a ÷ A^b = A^(a – b)
Therefore we have:
(2^20) ÷ (2^-7) = 2^[20 – (–7)] = 2^(20+7) = 2^27
To solve the quadratic equation given by 0=x^2-9x-20, we use the quadratic formula given by:
x=[-b+\- sqrt(b^2-4ac)]/(2a)
where,
a=1,b=-9,c=-20
thus substituting the above values into our formula we get:
x=[9+\-sqrt(9^2-4(-20*1))/(2*1)
x=[9+\-sqrt(161)]/2
x=[9+sqrt161]/2 or x=[9-sqrt161]/2
Answer:
Step-by-step explanation:
We have been given that there are 4 red marbles and 7 blue marbles and 5 yellow marbles in a bag. Monica will randomly pick two marbles out of the bag replacing the first marble before picking the second marble.
Since Monica will replace the first marble before picking the second marble, therefore, probability of both events will be independent and probability of occurring one event will not affect the probability of second event's occurring.
Since the probability of two independent compound events is always the product of probabilities of both events.
Now let us find probability of picking a red marble out of 16 (4+7+5) marbles.
Probability of picking blue ball out of 16 (4+7+5) marbles:
Now let us find probability of Monica picking a red and then a blue marble.
Therefore, the probability of picking a red and then blue marble is .
Answer:
Answer is B on Edge
F(x)=14-x
Step-by-step explanation:
