1/2a + 2/3(30)= 50
1/2a + 20 = 50
1/2a= 50-20
1/2a= 30
A= 30(2)
A= 60
The solution is 60.
Hope this helps!
The answer is 2
because 12 divided by 6 equals 2
Answer:
the correct answer is D
Step-by-step explanation:
if the 7 friends are splitting the cost they are dividing it among themselves.
Answer:
The answer is B) 0.57.
Step-by-step explanation:
In this problem we have to apply queueing theory.
It is a single server queueing problem.
The arrival rate is
and the service rate is
.
The proportion of time that the server is busy is now as the "server utilization"and can be calculated as:

where c is the number of server (in this case, one server).
Answer:
<em>c=6, d=2</em>
Step-by-step explanation:
<em>Equations
</em>
We must find the values of c and d that make the below equation be true
![\sqrt[3]{162x^cy^5}=3x^2y \sqrt[3]{6y^d}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%3D3x%5E2y%20%5Csqrt%5B3%5D%7B6y%5Ed%7D)
Let's cube both sides of the equation:
![\left (\sqrt[3]{162x^cy^5}\right )^3=\left (3x^2y \sqrt[3]{6y^d}\right)^3](https://tex.z-dn.net/?f=%5Cleft%20%28%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%5Cright%20%29%5E3%3D%5Cleft%20%283x%5E2y%20%5Csqrt%5B3%5D%7B6y%5Ed%7D%5Cright%29%5E3)
The left side just simplifies the cubic root with the cube:
![162x^cy^5=\left (3x^2y \sqrt[3]{6y^d}\right)^3](https://tex.z-dn.net/?f=162x%5Ecy%5E5%3D%5Cleft%20%283x%5E2y%20%5Csqrt%5B3%5D%7B6y%5Ed%7D%5Cright%29%5E3)
On the right side, we'll simplify the cubic root where possible and power what's outside of the root:

Simplifying

Equating the powers of x and y separately we find
c=6
5=3+d
d=2
The values are
