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lisov135 [29]
2 years ago
10

Bob, Bill, and Joe measured their heights. They figured out that the height of Bob is equal to b cm and he makes up 8/9 of the h

eight of Bill. The height of Bill makes up 3/32 of the height of Joe. How many times is Joe taller than Bob? Does the answer rely on the meaning of b?
Mathematics
1 answer:
andrezito [222]2 years ago
8 0

Answer:

Joe is 12 times taller than Bob

No the answer not rely on the meaning of b

Step-by-step explanation:

* Lets explain how the solve the problem

- The height of Bob is equal to b cm

- The height of Bob is 8/9 of the height of Bill

- Because 8/9 is less than one , then Bob is shorter than Bill

- The height of Bill makes up 3/32 of the height of Joe

* Lets write these information by mathematics relation

∵ The height of Bob is b

∵ The height of Bob is 8/9 height of Bill

∴ b = 8/9 the height of Bill

- Multiply both sides by 9

∴ 9 b = 8 the height of Bill

- Divide both sides by 8

∴ 9/8 b = the height of Bill

∴ The height of Bill is 9/8 b

∵ The height of Bill is 3/32 the height of Joe

∴ 9/8 b = 3/32 the height of Joe

- Multiply both sides by 32

∴ 36 b = 3 the height of Joe

- Divide both sides by 3

∴ 12 b = the height of Joe

∴ The height of Joe is 12 b

∵ b is the height of Bob

∴ The height of Joe is 12 times the height of Bob

∴ Joe is 12 times taller than Bob

- NO, the answer doesn't depend on b because the ratio between the

 heights of Joe and Bob doesn't change by the change of b

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Answer:

119.45 m

Step-by-step explanation:

Given:

When angle of elevation of the sun changes from 58° to 36° the length of shadow of a pole increases by 90 m.

To find:

Length of pole = ?

Solution:

Kindly refer to the attached image.

\triangle ABC represents the 1st angle of elevation of sun i.e.  58°

\triangle ABD represents the 2nd angle of elevation of sun i.e.  36°

Change in shadow is represented by CD = 90 m

Let height of pole, AB = h m

Let side BC = x m

Now, let us apply tangent rules in \triangle ABC, \triangle ABD one by one:

tan\theta = \dfrac{Perpendicular}{Base}\\\Rightarrow tan58^\circ=\dfrac{AB}{BC}\\\Rightarrow tan58^\circ=\dfrac{h}{x}\\\Rightarrow x = 0.624h ..... (1)

tan36^\circ = \dfrac{h}{x+90}

Putting value of x using equation (1):

tan36^\circ = \dfrac{h}{0.624h+90}\\\Rightarrow 0.726\times 0.624h+0.726\times 90 = h\\\Rightarrow h-0.453h =65.34\\\Rightarrow \bold{h = 119.45\ m}

119.45 m is the height of pole.

7 0
2 years ago
Dan had 2 1/2 cookies and ate 1/2 of a cookie. Of the original number of cookies, the fractional part that he ate was
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Answer:

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Step-by-step explanation:

Dan has 2 1/2 cookies and ate 1/2, so we can just subtract the 2 1/2-1/2

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fomenos

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Step-by-step explanation:

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