An equation in the form
is the line
that goes through the origins and whose tangent equates
. In general, any equation in the form
is the equation of a line.
You need to use the angle sum of a triangle in triangle CAD to express y in term of x
for triangla CAD , y = (180 -x) /2
180 = 3x + [ (180-x)/2]
x = 36
hope this helps
If there are real roots to be found for this polynomial, the Rational Root Theorem and synthetic division are the best way to find them. I teach from a book that uses c and d for the possible roots of the polynomial. C is our constant, 2, and d is the leading coefficient, 1. The factors of 2 are +/- 1 and +/-2. The factors for 1 are +/-1 only. Meaning, in all, there are 4 possibilities as roots for this polynomial. But there are only 3 total (because our polynomial is a third degree), so we have to find the first one, at least, from our possibilities above. Let's try x = -1, factor form (x + 1). If there is no remainder when we do the synthetic division, then -1 is a root. Put -1 outside the "box" and the coefficients from the polynomial inside: -1 (1 2 -1 -2). Bring down the first coefficient of 1 and multiply it by the -1 outside to get -1. Put that -1 up under the 2 and add to get 1. Multiply 1 times the -1 to get -1 and put that -1 up under the -1 and add to get -2. -1 times -2 is 2, and -2 + 2 = 0. So we have our first root of (x+1). The numbers we get when we do the addition along the way are the coefficients of our new polynomial, the depressed polynomial (NOT a sad one cuz it hates math, but a new polynomial that is one degree less than that of which we started!). The new polynomial is
. That can also be factored to find the remaining 2 roots. Use standard factoring to find that the other 2 solutions are (x+2) and (x-1). Our solutions then are x = -2, -1, 1, choice B from above.
In order to find the sum of the given rational expressions above, here are the steps.
Firstly, you need to find the LCM of the least common denominator.
So it would look like this:
<span>3x-1 + 3x (3x-1)(x-1) + (2x)(3x)
------ ------- = ---------------------------
2x x-1 2x(x-1)
3x^2-4x+1+6x^2
----------------------
2x(x-1)
And the final result would be this:
9x^2-4x+1
--------------
2x(x-1)
</span>9x^2-4x+1
--------------
2x^2-2x
<span>
Hope that this is the answer that you are looking for.
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