Answer:
k = 11.
Step-by-step explanation:
y = x^2 - 5x + k
dy/dx = 2x - 5 = the slope of the tangent to the curve
The slope of the normal = -1/(2x - 5)
The line 3y + x =25 is normal to the curve so finding its slope:
3y = 25 - x
y = -1/3 x + 25/3 <------- Slope is -1/3
So at the point of intersection with the curve, if the line is normal to the curve:
-1/3 = -1 / (2x - 5)
2x - 5 = 3 giving x = 4.
Substituting for x in y = x^2 - 5x + k:
When x = 4, y = (4)^2 - 5*4 + k
y = 16 - 20 + k
so y = k - 4.
From the equation y = -1/3 x + 25/3, at x = 4
y = (-1/3)*4 + 25/3 = 21/3 = 7.
So y = k - 4 = 7
k = 7 + 4 = 11.
Maximum weight the bridge can support in kilograms is 101696
Step-by-step explanation:
- Step 1: Given capacity of bridge = 100 British tons. Find how many kilograms are equivalent to 1 British ton.
1 British ton = 2240 pounds
1 pound = 0.454 kg
⇒ 1 British ton = 2240 × 0.454 kg = 1016.96 kg
- Step 2: Find how many kilograms are in 100 British tons.
⇒ 100 × 1016.96 = 101696
Answer:
Option C - Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
Step-by-step explanation:
We are given;
n = 15
t-value = 1.66
Significance level;α = 0.05
So, DF = n - 1 = 15 - 1 = 14
From the one-sample t - table attached, we can see that the p - value of 0.06 at a t-value of 1.66 and a DF of 14
Now, since the P-value is 0.06,it is greater than the significance level of 0.05. Thus we do not reject the null hypothesis. We conclude that there is not sufficient evidence that the true diameter differs from 0.5 in.
Answer:
b) 36 inches
Step-by-step explanation:
Length of the wire = Outside circumference of the cylindrical tube * length of the cylinder
= 4 * 9
= 36 inches
Length of the wire will be same to the surface area of the cylinder
Surface area of cylinder = circumference * length
