Answer:
- 6 gallons per minute.
Step-by-step explanation:
Let the function that models the quantities of water, Q (in gallons) in a pool over time, t (in minutes), is
Q = a + bt ........... (1)
Now, Q(t = 0) is given to be 50 gallons.
So, a = 50 and b denotes the rate at which the quantity of water in the pool is decreasing and it is given by the slope of equation (1).
Now, two points on the graph are (0,50) and (1,44).
So, the slope = b = 
= - 6 gallons per minute.
Therefore, the equation of this situation is given by Q = 50 - 6t, where the slope is equal to - 6 gallons per minute. (Answer)
Answer:
48 hats and 104 shirts
Step-by-step explanation:
These are the equations you build from the problem:
h + s = 152
8.50h + 12s = 1656
This is how I solved them:
s= 152-h
8.5h + 12(152-h) = 1656
8.5h + 1824 - 12h = 1656
Solve for h
h= 48
Put this into first equation (h +s = 152) to get s
Answer:
$0.40 for each bottle of juice
Step-by-step explanation:
You have :
--------------
DE arc = ( pi ) ( AD ) ( 2.36 radians / 2 pi radians ) = ( 2/3 ) ( AB ) ( 2.36 radians / 2 )
DE arc = ( 2/3 ( AB ) ( 1.18 radians )
BC arc = ( pi ) ( AB ) ( 1.18 radians / 2 pi radians )
BC arc = ( AB ) ( 0.59 radians )
BC arc / DE arc = ( AB ) ( 0.59 radians ) / ( 2/3 ) ( AB ) ( 1.18 radians )
BC arc / DE arc = ( AB ) ( 0.59 rad ) / ( 2/3 ) ( AB ) ( 1.18 rad )
BC arc / DE arc = ( 3/2 ) ( .59 rad / 1.18 rad ) = 3/4 <-------
We are tasked to solved for the length of the ramp having an inclination of 15 degrees with the ground and 10 feet from the end of the ramp to the base of the building of the ground. Using trigonometric properties, we have a formula given an angle and the its opposite sides which is,
sin(Angle)=opposite/hypothenuse
hypothenuse would be the distance or the length of the ramp.
so we have,
sin(15)=10/hypothenuse
Cross-multiply, we have,
hypothenuse=10/sin(15)
using scientific calculator having a DEG mode,
hypothenuse=38.63703
Rounding of in nearest tenth we get,
hypothenuse=38.6 ft
Therefore, the ramp is 38.6 ft long
