Max is trying to prove to his friend that two reflections, one across the x-axis and another across the y-axis, will not result
2 answers:
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Answer:
a) 0.64mm
b) 7/25
Step-by-step explanation:
Felipe trabaja en una construcción ayuda a cotizar materiales entre ellos cables para diversos propósitos.El arquitecto le pidió cotizar un cable de 16/25 mm de diámetro. en los catálogos disponibles en as tiendas las medidas aparecen expresadas en números decimales como se muestra en la imagen
¿Que debe hacer felipe para saber el diámetro del cable que pidió el arquitecto?
¿que medida en forma de fracción le corresponde al cable que mide 0.28? ¿como lo determinaste? es urgenteeee GRACIAS
a) Dada la dimensión fraccionaria del cable expresada como 16/25 mm, dado que Felipe debe expresar esta fracción en decimal para obtener la medida requerida, dividiremos la expresión usando una división larga como se muestra en el anexo. Desde el archivo adjunto;
16/25 mm = 0,64 mm
b) La medida fraccionaria corresponde al cable que mide 0.28 se expresa como se muestra. Convertir 0,28 a fracción.
0.28 = 28/100 (Tenga en cuenta que dividimos por 100 porque hay dos valores decimales después del punto decimal)
Sobre la simplificación en su término más bajo
28/100 = 4 * 7/4 * 25
28/100 = 4/4 * 7/25
28/100 = 1 * 7/25
28/100 = 7/25
Por lo tanto, la medida fraccionaria que corresponde al cable que mide 0.28 es 7/25.
Answer:
1. The Venn diagrams are attached
2. When the statistics students number = 10·x + 3, we have;
The number of students that study
a. Algebra = 128/11
b. Statistic = 213/11
When the statistics students number = 2·x + 3, we have;
The number of students that study
a. Algebra = 16
b. Statistic = 15
Step-by-step explanation:
The parameters given are;
Total number of students = 30
Number of students that study algebra n(A) = x + 10
Number of students that study statistics n(B) = 10·x + 3
Number of student that study both algebra and statistics n(A∩B) = 4
Number of student that study only algebra n(A\B) = 2·x
Number of students that study neither algebra or statistics n(A∪B)' = 3
Therefore;
The number of students that study either algebra or statistics = n(A∪B)
From set theory we have;
n(A∪B) = n(A) + n(B) - n(A∩B)
n(A∪B) = 30 - 3 = 27
Therefore, we have;
n(A∪B) = x + 10 + 10·x + 3 - 4 = 27
11·x+13 = 27 + 4 = 31
11·x = 18
x = 18/11
The number of students that study
a. Algebra
n(A) = 18/11 + 10 = 128/11
b. Statistic
n(B) = 213/11
Hence, we have;
n(A - B) = n(A) - n(A∩B) = 128/11 - 4 = 84/11
Similarly, we have;
n(B - A) = n(B) - n(A∩B) = 213/11 - 4 = 169/11
However, assuming n(B) = (2·x + 3), we have;
n(A∪B) = n(A) + n(B) - n(A∩B)
n(A∪B) = 30 - 3 = 27
Therefore, we have;
n(A∪B) = x + 10 + 2·x + 3 - 4 = 27
2·x+3 + x + 10= 27 + 4 = 31
3·x = 18
x = 6
Therefore, the number of students that study
a. Algebra
n(A) = 16
b. Statistics
n(B) = 15
Hence, we have;
n(A - B) = n(A) - n(A∩B) = 16 - 4 = 12
Similarly, we have;
n(B - A) = n(B) - n(A∩B) = 15 - 4 = 11
The Venn diagrams can be presented as follows;
Answer:
Step-by-step explanation:
Let x represents the number of hours and y represents the number of miles.
We are told that Luz drives at an average speed of 45 miles per hour. She has driven for 3 hours and has traveled a distance of 135 miles.
We can see from our given information that slope of line is 45 as with each increase in number of hours (x), change in distance (y) is 45.
Since the equation of line in point-slope form is : , where m represents slope of line and
represents a point the line passes through.
Upon substituting our given values in point-slope form of equation we will get,
Therefore, the equation represented in point-slope form will be: .
Answer:
Here, the given function that represents the number of hours of daylight in New Orleans in 1994 is,
Where,
x = the number of days after March 21
The number of days from 1 January to march 21 = 80
If x = -80, then,
Therefore, the number of hours of daylight on January 1 are 9.38.
The number of days from march 21 to may 4 = 44
If x =44, then,
Therefore, the number of hours of daylight on May 4 are 13.27.
The number of days from October 28 to may 4 = 221
If x = 221, then,
Therefore, the number of hours of daylight on October 28 are 10.23.