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alexdok [17]
2 years ago
8

Max is trying to prove to his friend that two reflections, one across the x-axis and another across the y-axis, will not result

in a reflection across the line y = x for a pre-image in quadrant II. His friend Josiah is trying to prove that a reflection across the x-axis followed by a reflection across the y-axis will result in a reflection across the line y = x for a pre-image in quadrant II. Which student is correct, and which statements below will help him prove his conjecture? Check all that apply. Max is correct. O Josiah is correct. Taking the result from the first reflection (x, y) and applying the second mapping rule will result in (-X, -y), not (y x), which reflecting across the line y = x should give. If one reflects a figure first across the x-axis from quadrant II then reflects across the y-axis from quadrant II, the image will end up in quadrant IV. O A figure that is reflected from quadrant II to quadrant IV across the line y = x will have the coordinates of (-y).​
Mathematics
2 answers:
shtirl [24]2 years ago
7 0

Answer:

Max is correct

Taking the result from the first reflection (x, –y) and applying the second mapping rule will result in (–x, –y), not (y, x), which reflecting across the line y = x should give.

If one reflects a figure first across the x-axis from quadrant II then reflects across the y-axis from quadrant III, the image will end up in quadrant IV.

Step-by-step explanation

took the test on edge hope this helps

Leni [432]2 years ago
7 0

Answer:

1, 3, 4

TRUST ME I GOT IT RIGHT THE OTHER GUY IS WRONG

Step-by-step explanation:

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Vsevolod [243]

Answer: A movie ticket is $9 while a snack is $2

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2m + 3s = 24

Also if three movie tickets and four snacks cost $35, we can as well write another expression as follows;

3m + 4s = 35.

Now we have a pair of simultaneous equations which are

2m + 3s = 24 ----------(1)

3m + 4s = 35 ----------(2)

We shall solve this by using the elimination method, since none of the variables has a coefficient of 1. We'll start by multiplying equation (1) by 3 and multiplying equation (2) by 2 (so as to eliminate the m variable)

2m + 3s = 24 -------- x3

3m + 4s = 35 ---------x2

We now arrive at the following

6m + 9s = 72--------(3)

6m + 8s = 70--------(4)

Subtract equation (4) from equation (3) and we arrive at

s = 2

Having determined that s equals 2 we can now substitute for the value of a into equation (1)

2m + 3s = 24

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2m + 6 = 24

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2m + 6 - 6 = 24 - 6

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Divide both sides of the equation by 2

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2 years ago
Assemble the proof by dragging tiles to the statements and reasons columns.<br><br> PLEASE HELP
nataly862011 [7]

m<ABD = 52                               Given

BC bisects <ABD                        Given

m<ABC =  m<CBD                      Definition of angle bisector.

m<ABC +m<CBD = m<ABD        Angle addition postulate.

m<ABC +m<CBD = 52                Substitution

m<ABC + m<ABC= 52                Substitution

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2 years ago
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adell [148]
To calculate this, the Hardy-Weinberg principle can be used:

p² + 2pq + q² = 1 and p + q = 1

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q = √q² = √0.19 = 0.44

Since p + q = 1, then

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Answer:

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