Answer:
There are asymptotes at x = three-halves and x = negative one-third.
Step-by-step explanation:
f(x) = (x + 1)/ (6x^2 - 7x - 3)
= (x + 1)( / (6x^2 + 2x - 9x - 3)
= (x + 1) / (2x(3x + 1) - 3(3x + 1))
= (x + 1) / (2x - 3)(3x + 1)
Now x = 3/2 and x = -1/3 both make te denominator zero so these are both asymptotes.
I just got this question. I think the answer is 5.
I see the solution in three steps.
1.) RS ⊥ ST, RS ⊥ SQ, ∠STR ≅ ∠SQR | Given
2.) RS<span>≅RS | Reflexive Property
3.) </span><span>△RST ≅ △RSQ | AAS Triangle Congruence Property</span>
Answer:
492 0/10
Step-by-step explanation:
We have that the perimeter is 4 times the length of the side, now we know that this side "l" is given by:
l = 4 in * 24 + 23 * 5 ft
l = 96 in + 115 ft
Now, we pass the inches to pes, knowing that 1 foot equals 12 inches, so
96 in * 1 ft / 12 in = 8 ft
therefore replacing it remains:
l = 8 ft + 115 ft
l = 123 ft
now the perimeter:
p = 123 * 4
p = 492
to change to a mixed number:
4920/10 = 492 0/10
