I'm pretty sure simplest form would still be 865:2678
I could be wrong tho
Answer:
She will pay $7,500 interest over the 5 years
She will have to pay back $17,500 in total
Step-by-step explanation:
Let us revise the rule of the simple interest
<em>I</em> = <em>Prt</em> and <em>A</em> = <em>P</em>(1 +<em> rt</em>)
, where:
- A = Total Accrued Amount (principal + interest)
- r = Rate of Interest per year in decimal
- t = Time Period involved in months or years
∵ Leah borrows £10,000 over 5 years at a simple interest rate of 15%.
∴ P = 10,000
∴ t = 5
∴ r = 15% =
= 0.15
→ Substitute them in the first rule to find the interest
∵ I = 10,000(0.15)(5)
∴ I = 7,500
∴ She will pay $7,500 interest over the 5 years
→ Let us find A
∵ A = 10,000(1 + 0.15×5)
∴ A = 17,500
∴ She will have to pay back $17,500 in total
Answer:
See below
Step-by-step explanation:
<h3>Continuation of the question</h3>
<u>Data in the table:</u>
<u>PH 4 5 6 7 8 9 10 11 </u>
<u>Bacteria 116 120 131 136 141 151 148 163</u>
- <em>Create a scatter plot to represent the data: Based on the data and your scatter plot, what do you think a good linear function would be to represent the data?</em>
<h3>Solution</h3>
<em>See attached for scatter plot</em>
We can see the chart is close to linear function. Let's build one based on data in the table
<u>The line will be in the form of:</u>
<u>If we use two points and get the equation</u>
<u>Finding the slope:</u>
- m = (141-116)/(8-4) = 25/4 = 6.25
<u>Then, finding y-intercept:</u>
- 116 = 6.25*4 + b
- b = 116 - 25 = 91
<u>So the line is:</u>
<em>Note: This is approximate best fit graph and it is attached as well. Exact formula for the line is built by using different method and is very close to the one above</em>
Answer:
P(t) = 1000e^(0.01155)t
Step-by-step explanation:
Let the population of barangay be expressed according to the exponential formula;
P(t) = P0e^kt
P(t) is the population of the country after t years
P0 is the initial population
t is the time
If barangay has 1000 initially, this means that P0 = 1000
If the population doubles after 60years then;
at t = 60, P(t) = 2P0
Substitute into the formula
2P0 = P0e^k(60)
2 = e^60k
Apply ln to both sides
ln2 = lne^60k
ln2 = 60k
k = ln2/60
k = 0.01155
Substitute k = 0.01155 and P0 into the expression
P(t) = 1000e^(0.01155)t
Hence an exponential model for barangay's population is
P(t) = 1000e^(0.01155)t
I think it is fair becasue you have the chance to win more than to lose point if get 1 or 6 you dont get nothing so that not a lose