Question

Spinner i is divided into four equal sections labeled 2, 3, 4 and 5. spinner ii is divided into five equal sections labeled 1, 3, 5, 7 and 9. if each spinner is spun and the resulting numbers are multiplied, what is the probability that the product is a two-digit even number? express your answer as a common fraction.

Answer 1

The probability is 7/20.

There are 20 outcomes in the sample space:
2(1)   2(3)   2(5)   2(7)   2(9)
3(1)   3(3)   3(5)   3(7)   3(9)
4(1)   4(3)   4(5)   4(7)   4(9)
5(1)   5(3)   5(5)   5(7)   5(9)

Out of these, 14 are two digit products.  Out of those 14, only 7 are odd.  Thus the probability is 7/20.

Answer 2

Answer: The probability is p = 0.35

Step-by-step explanation:

The data is:

Spinner 1 is labeled 2, 3, 4 and 5

Spinner 2 is labeled 1, 3, 5, 7 and 9

then the first spinner has 4 options and the second one has 5 options, so we have a total of 4*5 = 20 possible outcomes of spurning both spinners.

The options where the product is a two-digit even number are:

2*5 = 10

2*7 = 14

2*9 = 18

4*3 = 12

4*5 = 20

4*7 = 28  

4*9 = 36

so we have a total of 7 combinations where the product of both numbers is a two-digit number.

The probability of this event happening is equal to the number of combinations where this event happens, divide the total number of combinations, so we have:

P = 7/20 = 0.35