Solve z3+3z2−25z−75=0 .

1 answer:

3 0

z^3 + 3z^2 -25z - 75 = 0
Factor out common terms in the first two terms, then in the last two terms
z^2(z+3)−25(z+3)=0
Factor out the common term z+3
(z+3)(z^2−25)=0
Ask: When will (z+3)(z^2−25) equal zero?
When z+3=0 or z^2−25=0
Solve each of the 2 equations above
z=−3,±5

Hope this helps

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Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:

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