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Tamiku [17]
2 years ago
5

The school play started at 2:10pm and ended at 3:22pm. How long did the play last?

Mathematics
2 answers:
Allushta [10]2 years ago
7 0

Answer:

The play lasted 1 hour and 12 minutes.

Step-by-step explanation:

Start: 2:10 pm. End: 3:22 pm.

3 hours - 2 hours = 1 hour

Start: 2:10 pm. End: 3:22 pm.

22 minutes - 10 minutes = 12 minutes

The play lasted 1 hour and 12 minutes.

Anna35 [415]2 years ago
3 0
2:10=>3:10, was 1 hour
3:10=> 3:22, were 12 minutes

the play last 1 hour 12 minutes (or 60+12= 72 minutes).
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Mr. Malloy wants to make sure Amo and Javier get the best possible grade after five tests and can either give a grade based on t
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The data has been properly arranged in tabular form and is shown below in the image.

First we need to find the mean and median of scores of both students.

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For both the students, value of Median is larger then the mean. So in order to give the best possible grade Mr. Malloy should use the median score for both students.

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2 years ago
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The table shows ordered pairs of the function y = 16 + 0.5x . Which ordered pair could be the missing values represented by (x,
lawyer [7]

The <u><em>correct answer</em></u> is:

(8, 20).

Explanation:

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y=16+0.5(0) = 16+0 = 16 ≠ 18. This is not the correct option.

y=16+0.5(5) = 16+2.5 = 18.5 ≠ 19.5. This is not the correct option.

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2 years ago
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2,
mariarad [96]

Answer:

Insurance will pay $250,000 and Ronaldo will pay $90,000

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50/250 means 50 is the maxi9$50,000 per person for body injury liability while 250 means $250,000 maximum for one accident for body injury liability claim.

18 children each was awarded $20,000 as a result of lawsuit

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8 0
2 years ago
Match the following items.
Margarita [4]

Answer:

1. m\angle ECB=50\\2. m\textrm{ arc BC}=100\\3. m\textrm{ arc CD}=80\\4. m\angle DCF=40

Step-by-step explanation:

Given:

\angle DBC=40°

From the triangle, using the theorem that center angle by an arc is twice the angle it subtend at the circumference.

m\textrm{ arc CD}=2\times \angle DBC\\m\textrm{ arc CD}=2\times 40=80

Also, the diameter of the circle is BD. As per the theorem that says that angle subtended by the diameter at the circumference is always 90°,

m\angle BCD=90

From the Δ BCD, which is a right angled triangle,

m\angle DBC+m\angle BDC=90\textrm{ (right angled triangle)}\\40+m\angle BDC=90\\m\angle BDC=90-40=50

Now, using the theorem that angle between the tangent and a chord is equal to the angle subtended by the same chord at the circumference.

Here, chords CD and BC subtend angles 40 and 50 at the circumference as shown in the diagram by angles m\angle DBC\textrm{ and }m\angle BDC and EF is a tangent to the circle at point C.

Therefore, m\angle DCF=m\angle DBC=40\\m\angle ECB=m\angle BDC=50

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m\angle DCF=50\\\therefore m\textrm{ arc BC}=2\times m\angle DCF=2\times 50=100

Hence, all the angles are as follows:

1. m\angle ECB=50\\2. m\textrm{ arc BC}=100\\3. m\textrm{ arc CD}=80\\4. m\angle DCF=40

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2 years ago
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