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2 years ago

The school play started at 2:10pm and ended at 3:22pm. How long did the play last?

Mathematics

2 answers:

Allushta [10]2 years ago

7 0

Answer:

The play lasted 1 hour and 12 minutes.

Step-by-step explanation:

Start: 2:10 pm. End: 3:22 pm.

3 hours - 2 hours = 1 hour

Start: 2:10 pm. End: 3:22 pm.

22 minutes - 10 minutes = 12 minutes

The play lasted 1 hour and 12 minutes.

Anna35 [415]2 years ago

3 0

2:10=>3:10, was 1 hour
3:10=> 3:22, were 12 minutes

the play last 1 hour 12 minutes (or 60+12= 72 minutes).

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Dima020 [189]

Answer:

x=15

Step-by-step explanation:

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then subtract 5x from both sides and you have -3x=-45

then finally divide -3 from -45 to get x=15

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2 years ago

Find the GCF of 44j5k4 and 121j2k6.

BartSMP [9]

Answer:

D. $11j^2k^4$

Step-by-step explanation:

We are asked to find the GCF of $44j^5k^4\text{ and }121j^2k^6$ .

Since we know that GCF of two numbers is the greatest number that is a factor of both of them.

First of all we will GCF of 44 and 121.

Factors of 44 are: 1, 2, 4, 11, 22, 44.

Factors of 121 are: 1, 11, 11, 121.

We can see that greatest common factor of 44 and 121 is 11.

Now let us find GCF of $j^5\text{ and }j^2$ .

Factors of $j^5$ are: $j*j*j*j*j$

Factors of $j^2$ are: $j*j$

We can see that greatest common factor of $j^5\text{ and }j^2$ is $j*j=j^2$ .

Now let us find GCF of $k^4\text{ and }k^6$ .

Factors of $k^4$ are: $k*k*k*k$

Factors of $k^6$ are: $k*k*k*k*k*k$

We can see that greatest common factor of $k^4\text{ and }k^6$ is $k*k*k*k=k^4$ .

Upon combining our all GCFs we will get,

$11j^2k^4$

Therefore, GCF of $44j^5k^4\text{ and }121j^2k^6$ is $11j^2k^4$ and option D is the correct choice.

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2 years ago

Read 2 more answers

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Answer:

Step-by-step explanation:

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We would first determine the mean.

Mean = sum of terms in the data/ number of terms in the data.

Sum of terms =

663 + 273 + 410 + 622 + 174 + 374

= 2516

Number of terms = 6

Mean = 2516/6 = 419.33

Standard deviation = √summation(x - m)^2/n

summation(x - m)^2/n = (663 - 429.33)^2 + (273 - 419.33)^2 + (410 - 419.33)^2 + (622 - 419.33)^2 + (174 - 419.33)^2 + (374 - 419.33)^2

= 179417.9334/6 = 29902.9889

Standard deviation = √29902.9889

= 172.9

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Answer:

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Savatey [412]

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