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devlian [24]
2 years ago
13

To the right are the outcomes that are possible when a couple has three children. assume that boys and girls are equally​ likely

, so that the eight simple events are equally likely. find the probability that when a couple has three​ children, there is exactly 1 girl.
Mathematics
1 answer:
hoa [83]2 years ago
7 0

The all possible eight outcomes of boy or girl birth when a couple have three children is

(GBB) , (GBG), (GGB) , (GGG), (BBG), (BGB), (BGG), (BBB)

Where B represents boy and G represents Girl

The probability that having exactly 1 girl is

= Number of outcomes with one girl / Total numbers of outcomes

Now Number of outcomes with only one girl = GBB, BGB, BBG = 3

So the probability will be

The probability that having exactly 1 girl is = 3/8 = 0.375

The probability that when a couple has three​ children, there is exactly 1 girl is 0.375

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Answer:

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2 years ago
A set of speakers costs $22 and songs cost $1.25 each. The sales tax rate is 7.5%. The expression 0.075(22 + 1.25s) can be used
kykrilka [37]

Answer:

1.65 + 0.09s

Step-by-step explanation:

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4 0
1 year ago
For the equation ae^ct=d, solve for the variable t in terms of a,c, and d. Express your answer in terms of the natural logarithm
saveliy_v [14]

We have been given an equation ae^{ct}=d. We are asked to solve the equation for t.

First of all, we will divide both sides of equation by a.

\frac{ae^{ct}}{a}=\frac{d}{a}

e^{ct}=\frac{d}{a}

Now we will take natural log on both sides.

\text{ln}(e^{ct})=\text{ln}(\frac{d}{a})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

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We know that \text{ln}(e)=1, so we will get:

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t=\frac{\text{ln}(\frac{d}{a})}{c}

Therefore, our solution would be t=\frac{\text{ln}(\frac{d}{a})}{c}.

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