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1 year ago

Which describes the correlation shown in the scatterplot?

Mathematics

2 answers:

velikii [3]1 year ago

9 0

Answer:

Step-by-step explanation: As you can see, the correlation goes up and down, this does not represent positive nor negative. Therefore, C would be your final answer.

Alex_Xolod [135]1 year ago

8 0

Answer: C) There is no positive or negative correlation

A positive correlation is one where the values are increasing, and the line of dots are clearly going down to up.

A negative correlation is the opposite. The values are decreasing, and the line goes from up to down.

This correlation is one that is neither positive or negative. It is a straight line where the values neither increase nor decrease.

Hope this helps comment below for more questions :)

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It is known that driving can be difficult in regions where winter conditions involve snow-covered roads. For cars equipped with

noname [10]

Answer:

The null and alternative hypothesis for this test are

$H_0: \mu\ge 215\\\\H_1: \mu< 215$

Step-by-step explanation:

If we perform a hypothesis test, we can reject or not reject the null hypothesis.

To conclude that the tires have a decreased stopping distance (μ<215), we should state the null hypothesis $H_0: \mu\ge 215$ and then go on with the analysis to reject it (or not).

If the null hypothesis is rejected, the claim of the manufacturer is rigth.

The alternative hypothesis would be $H_1: \mu$ , that would turn rigth if the null hypothesis is rejected.

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1 year ago

According to a "how to stop bullying" Web site, 15% of students report experiencing bullying one to three times within the most

AlekseyPX

Answer:

His 95% confidence interval is (0.065, 0.155).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 186, \pi = 0.11$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 - 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.065$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 + 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.155$

His 95% confidence interval is (0.065, 0.155).

4 0

1 year ago

(1 point) Rework problem 15 in section 2 of Chapter 5 of your textbook about the growing suburb and the declining city using the

Vanyuwa [196]

Answer:

16 years

Step-by-step explanation:

Let x represent the number of years. The suburb population is growing at a rate of 5000 per year after x years, it can be represented by the equation:

320000 + 5000x

The city population is declining at a rate of 14000 per year after x years, it can be represented by the equation:

624000 - 14000x

The number of years for the city and suburb population to be equal can be gotten from:

320000 + 5000x = 624000 - 14000x

14000x + 5000x = 624000 - 320000

19000x = 304000

x = 304000 / 19000

x = 16

In 16 years the populations of the suburb and the city be equal

6 0

1 year ago

A team of 10 players is to be selected from a class of 6 girls and 7 boys. Match each scenario to its probability. You have to d

tankabanditka [31]

The selection of r objects out of n is done in

$C(n, r)= \frac{n!}{r!(n-r)!}$ many ways.

The total number of selections 10 that we can make from 6+7=13 students is

$C(13,10)= \frac{13!}{3!(10)!}= \frac{13*12*11*10!}{3*2*1*10!}= \frac{13*12*11}{3*2}= 286$
thus, the sample space of the experiment is 286

A.
"The probability that a randomly chosen team includes all 6 girls in the class."

total number of group of 10 which include all girls is C(7, 4), because the girls are fixed, and the remaining 4 is to be completed from the 7 boys, which can be done in C(7, 4) many ways.

 $C(7, 4)= \frac{7!}{4!3!}= \frac{7*6*5*4!}{4!*3*2*1}= \frac{7*6*5}{3*2}=35$

P(all 6 girls chosen)=35/286=0.12

B.
"The probability that a randomly chosen team has 3 girls and 7 boys."

with the same logic as in A, the number of groups were all 7 boys are in, is

 $C(6, 3)= \frac{6!}{3!3!}= \frac{6*5*4*3!}{3!3!}= \frac{6*5*4}{3*2*1}=20$

so the probability is 20/286=0.07

C.
"The probability that a randomly chosen team has either 4 or 6 boys."

case 1: the team has 4 boys and 6 girls

this was already calculated in part A, it is 0.12.

case 2, the team has 6 boys and 4 girls.

there C(7, 6)*C(6, 4) ,many ways of doing this, because any selection of the boys which can be done in C(7, 6) ways, can be combined with any selection of the girls.

 $C(7, 6)*C(6, 4)= \frac{7!}{6!1}* \frac{6!}{4!2!} =7*15= 105$

the probability is 105/286=0.367

since case 1 and case 2 are disjoint, that is either one or the other happen, then we add the probabilities:

0.12+0.367=0.487 (approximately = 0.49)

D.
"The probability that a randomly chosen team has 5 girls and 5 boys."

selecting 5 boys and 5 girls can be done in

 $C(7, 5)*C(6,5)= \frac{7!}{5!2} * \frac{6!}{5!1}=21*6=126$

many ways,

so the probability is 126/286=0.44

6 0

2 years ago

Read 2 more answers

PLZ HELP! Oliver is 8 feet above the surface of the water. There is a school of fish 10 feet below the surface. A ledge with som

qwelly [4]

Answer:

26 feet, Oliver will have to travel 26 feet deep.

Step-by-step explanation:

8 feet added to 18 feet will be your answer.

8 0

1 year ago