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2 years ago

Divide. Round to the nearest tenth. .48 divided by 9.23

Mathematics

2 answers:

julsineya [31]2 years ago

4 0

Answer:

Step-by-step explanation:

.48/9.23 turns into 48/923 because however amount of decimal places you move the dividend to make it a whole number is the same amount of decimal places you move the divisor. When you divide 48/923, you get about .05200, which rounds to .1

Kobotan [32]2 years ago

3 0

I believe the answer is 0.1

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Kim bought 12 boxes of drinks

salantis [7]

Answer:

The amount Kim sold each reduced price drink is $1.25 each

Step-by-step explanation:

The number of boxes of drinks Kim bought = 12 boxes

The amount Kim paid for each box = $15

The number of drinks in each box = 12 drinks

The amount Kim sild 3/4 of the drinks = $1.50 each

The amount Kim sold the remaining drinks = At a reduced rate

The amount of profit Kim made = 15%

Therefore, we have;

The total amount Kim bought the whole drinks = 12 × $15 = $180

The total number of drinks = 12 × 12 = 144 drinks

3/4 of the drinks = 3/4×144 = 108 drinks

The amount Kim sold the 108 drinks = 108 × $1.5 = $162

The amount of profit Kim made = 15%

Therefore;

(((The total amount Kim sold the whole drinks) - (The total amount Kim bought the whole drinks))/(The total amount Kim bought the whole drinks)) × 100 = Percentage profit

(((The total amount Kim sold the whole drinks) - ($180))/($180)) × 100 = 15%

The total amount Kim sold the whole drinks = 0.15×$180 + $180 = $207

The total number of the remainder of the drinks = 144 - 108 = 36 drinks

The amount Kim sold the remainder of the drinks = $207 - $162 = $45

The amount Kim sold each of the remainder of the drinks at reduced price = $45/36 = $1.25

Therefore, the amount Kim sold each reduced price drink = $1.25 each.

8 0

2 years ago

Kenji uses the diagram to determine the quotient of StartFraction 9 Over 10 EndFraction and Three-fifths. A fraction bar labeled

IRISSAK [1]

Answer:

Kenji counted by One fifth instead of three fifths.

Step-by-step explanation:

When you count by one fifths to equal the 9/10 then you would get 4 1/2 as an answer. the answer is counting by three fifths to equal 1 1/2.

4 0

2 years ago

Read 3 more answers

A recent article in Business Week listed the "Best Small Companies." We are interested in the current results of the companies'

Sindrei [870]

Answer:

(i) The estimated regression equation is;

$\hat y$ ≈ 1.6896 + 0.0604·X

The coefficient of 'X' indicates that $\hat y$ increase by a multiple of 0.0604 for each million dollar increase in sales, X

(ii) The estimated earnings for the company is approximately $4.7096 million

(iii) The standard error of estimate is approximately 29.34

The high standard error of estimate indicates that individual mean do not accurately represent the population mean

(iv) The coefficient of determination is approximately 0.57925

The coefficient of determination indicates that the probability of the coordinate of a new point of data to be located on the line is 0.57925

Step-by-step explanation:

The given data is presented as follows;

$\begin{array}{ccc}Sales \ (\$million)&&Earning \ (\$million) \\89.2&&4.9\\18.6&&4.4\\18.2&&1.3\\71.7&&8\\58.6&&6.6\\46.8&&4.1\\17.5&&2.6\\11.9&&1.7\end{array}$

(i) From the data, we have;

The regression equation can be presented as follows;

$\hat y$ = b₀ + b₁·x

Where;

b₁ = The slope given as follows;

$b_1 = \dfrac{\Sigma(x_i - \overline x) \cdot (y_i - \overline y)}{\Sigma(x_i - \overline x)^2}$

b₀ = $\overline y$ - b₁· $\overline x$

From the data, we have;

${\Sigma(x_i - \overline x) \cdot (y_i - \overline y)}$ = 364.05

$\Sigma(x_i - \overline x)^2}$ = 6,027.259

$\overline y$ = 4.2

$\overline x$ = 41.5625

∴ b₁ = 364.05/6,027.259 ≈ 0.06040059005

b₀ = 4.2 - 0.06040059005 × 41.5625 ≈ 1.68960047605 ≈ 1.69

Therefore, we have the regression equation as follows;

$\hat y$ ≈ 1.6896 + 0.0604·X

The coefficient of 'X' indicates that the earnings increase by a multiple of 0.0604 for each million dollar increase in sales

(ii) For the small company, we have;

X = $50.0 million, therefore, we get;

$\hat y$ = 1.6896 + 0.0604 × 50 = 4.7096

The estimated earnings for the company, $\hat y$ = 4.7096 million

(iii) The standard error of estimate, σ, is given by the following formula;

$\sigma =\sqrt{\dfrac{\sum \left (x_i-\mu \right )^{2} }{n - 1}}$

Where;

n = The sample size

Therefore, we have;

$\sigma =\sqrt{\dfrac{6,027.259 }{8 - 1}} \approx 29.34$

The standard error of estimate, σ ≈ 29.34

The high standard error of estimate indicates that it is very unlikely that a given mean value within the data is a representation of the true population mean

(iv) The coefficient of determination (R Square) is given as follows;

$R^2 = \dfrac{SSR}{SST}$

Where;

SSR = The Sum of Squared Regression ≈ 21.9884

SST = The total variation in the sample ≈ 37.96

Therefore, R² ≈ 21.9884/37.96 ≈ 0.57925

The coefficient of determination, R² ≈ 0.57925.

Therefore, by the coefficient of determination, the likelihood of a new introduced data point to located on the line is 0.57925

6 0

2 years ago

The speed of a roller coaster depends on the height it drops from. Which expression represents the speed of a roller coaster if

kotegsom [21]

The correct answer is Choice A.

If the speed is a function of the height, we would use the notation speed(height). On the left, we put the output and in the parenthesis we put the input.

We can change the word height to 200, because we know the height is 200.

7 0

2 years ago

A study was recently conducted at a major university to estimate the difference in the proportion of business school graduates w

sveta [45]

Answer:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$p_A$ represent the real population proportion for business

$\hat p_A =\frac{75}{400}=0.1875$ represent the estimated proportion for Business

$n_A=400$ is the sample size required for Business

$p_B$ represent the real population proportion for non Business

$\hat p_B =\frac{137}{500}=0.274$ represent the estimated proportion for non Business

$n_B=500$ is the sample size required for non Business

$z$ represent the critical value for the margin of error

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$(0.1875-0.274) - 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.1412$

$(0.1875-0.274) + 1.96 \sqrt{\frac{0.1875(1-0.1875)}{400} +\frac{0.274(1-0.274)}{500}}=-0.0318$

And the 95% confidence interval would be given (-0.1412;-0.0318).

We are confident at 95% that the difference between the two proportions is between $-0.1412 \leq p_A -p_B \leq -0.0318$

7 0

1 year ago