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AleksAgata [21]
1 year ago
14

a machine factory produces 2 parts per second. one shift is 10 hours long. what is the production rate, in parts per shift? ente

r your answer in the box.
Mathematics
2 answers:
Natasha_Volkova [10]1 year ago
4 0

Answer:

The answer will be 72,00 I hope you all have a nice day if you are seeing this and get a great big fat A+

Step-by-step explanation:

seraphim [82]1 year ago
3 0
The way to work out how many parts there are per shift would be as follows: if there are 2 parts produced every second, this means there are 120 produced every minute (60 times 2), and if you then multiply this 120 again to work out how many parts are made in an hour you will get 7,200. If you times this by 10 again you will get 72,000 parts made in a 10 hour shift.
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If a cow has a mass of 9×102 kilograms, and a blue whale has a mass of 1.8×105 kilograms, which of these statements is true?
lana66690 [7]

Answer:

The mass of the Blue whale is 200 times the mass of the cow

Step-by-step explanation:

Given

Mass of Cow = 9 * 10² kg

Mass of Blue Whale = 1.8 * 10⁵ kg

Required

Determine the relationship between both weights

Represent the mass of the cow with C and the mass of the whale with B

C = 9 * 10^2kg

C = 9 *100kg

C = 900kg

B = 1.8 * 10^5kg

B = 1.8 * 100000kg

B = 180000kg

Divide the bigger weight by the smaller weight

\frac{B}{C} = \frac{180000kg}{900kg}

\frac{B}{C} = \frac{180000}{900}

\frac{B}{C} = {200}{}

Multiply both sides by C

C * \frac{B}{C} = {200}{} * C

B = {200}{} * C

B = 200}C

<em>From the expression above, it can be concluded that the mass of the Blue whale is 200 times the mass of the cow</em>

7 0
1 year ago
Explain how complex fractions can be used to solve problems involving ratios
Kisachek [45]
When you have ratios and some unknowns you can create complex fractions from them.Bring them to the same denominator and solve for X.
8 0
1 year ago
A total of 165 people attended the opening night of a school play. Adults were charged $6, and children were charged $2. The tot
arlik [135]
-------------------------------------------------------------------------
Given Information
-------------------------------------------------------------------------
Total number of people = 165
Adult = $6
Child = $2
Total collected = $618

-------------------------------------------------------------------------
Assumptions 
-------------------------------------------------------------------------
Let x be the number of adults and y be the number of children

-------------------------------------------------------------------------
Form equations
-------------------------------------------------------------------------
Total number of people
x + y = 165
Total amount collected 
6x + 2y = 618

-------------------------------------------------------------------------
Ans: The two equations are x + y = 165 and 6x + 2y = 618
-------------------------------------------------------------------------


The question is not asking for it but if you need to solve the equation to find the answer to x and y

-------------------------------------------------------------------------
Present the two equations and solve for x and y
-------------------------------------------------------------------------
x + y = 165          ------------------------- (eqn 1)
6x + 2y = 618      ------------------------- (eqn 2)

(eqn 1) : 
x + y = 165
x = 165 - y -------------------------  substitute into (eqn 2)

6(165 - y) + 2y = 618
990 - 6y + 2y = 618
4y = 990 - 618
4y = 372
y = 93 -------------------------  substitute into (eqn 1)

x + y = 165
x + 93 = 165
x = 165 - 93
x = 72 

x = 72 and y = 93

-------------------------------------------------------------------------
Ans: 72 adults and 93 children
-------------------------------------------------------------------------
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The ribbon would be 9 yards long
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The sample size of the data set is 9.The range of the data is 10 - 15.
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A plot of the histogram n shown in the figure.The data is skewed toward a value of 10, which has the largest frequency of 3.The average is 12, and the median is 12.

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