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ElenaW [278]
1 year ago
8

Is the data set "the colors of the leaves on a branch" quantitative or qualitative? If it is quantitative, is it discrete or con

tinuous? a. quantitative, discrete c. qualitative b. quantitative, continuous d. neither Please select the best answer from the choices provided A B C D
Mathematics
2 answers:
Mice21 [21]1 year ago
6 0

Answer:

Option C. qualitative

Step-by-step explanation:

A qualitative variable is the type of variable that can't be numerically expressed but can be categorized. The colors of the leaves on a branch can be categorized as green, yellow and orange etc. Thus, the colors of the leaves is a qualitative variable. So, the correct option is C.

MrMuchimi1 year ago
6 0

Answer:

asfddasf

Step-by-step explanation:

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Jabari is thinking of three numbers. The greatest number is twice as large as the least number. The middle number is three more
Likurg_2 [28]

Answer:

  18, 21, 36

Step-by-step explanation:

Let L represent the least number. Then the greatest is 2L and the middle number is (L+3). Their sum is ...

  L +(2L) +(L+3) = 75

  4L = 72 . . . . . . . . . subtract 2, collect terms

  L = 18 . . . . . . . . . . . divide by 4

  L+3 = 21

  2L = 36

The numbers are 18, 21, and 36.

5 0
1 year ago
Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −
Korolek [52]

The vector field

\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k

has curl

\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath

Parameterize S by

\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k

where

\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}

with 0\le u\le3 and 0\le v\le2\pi.

Take the normal vector to S to be

\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k

Then by Stokes' theorem we have

\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{2\pi}\int_0^3(\nabla\times\vec F)(\vec s(u,v))\cdot\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^3u^3(2u\cos^3v\sin(u^2-9)+\cos^3v\sin v+2u\sin^3v+\cos v\sin^3v)\,\mathrm du\,\mathrm dv

which has a value of 0, since each component integral is 0:

\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0

4 0
1 year ago
The volume of clay used to build a cylindrical pillar with a height of 9 centimeters is 324π cubic centimeters. The area of the
stealth61 [152]
Area=height times base (for some prisms including cylinders)
vcylinder=hpir²
h=height
therefor pir²=base area
vcylinder=height times aeraofbase

 

given
h=9
v=324pi
324pi=9(basearea)
divide both sides by 9
36pi=areabase

the area of te base is 36pi square cm (put 36 in the blank since th pi is alredy there)
3 0
2 years ago
Read 2 more answers
Janet can read 3.6 pages of a book in a minute. If she read for 2.71 minutes. How much would have she had read
Aliun [14]

Answer:

9.76 pages

Step-by-step explanation:

multiply 3.6 times 2 to get 7.2. Then multiply 3.6 times .71 to get 2.56 then add 7.2 and 2.56 to get <u>9.76</u> as your answer.

8 0
2 years ago
Ali and Felicia analyzed the patterns of equivalent ratios for StartFraction 3 Over 8 EndFraction in the table below.
Romashka [77]

Answer:

its a

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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