Jane is one of 50 students to take a standardized math test that includes 100 multiple choice questions. If she has the highest
1 answer:
You might be interested in
Given functin is :
We know that the domain of the expression is all real numbers except where the expression is undefined. In given function, there is no real number that makes the expression undefined. Hence domain is all real numbers.
Domain: (-∞,∞)
Range is the set of y-values obtained by plugging values from domain so the range will also same.
Range: (-∞,∞)
If we increase value of x then y-value will also increase so that means it is an INCREASING function. You can also verify that from graph.
It crosses x and y-axes both at the origin
Hence x-intercept=0 and y-intercept=0
Graph is not symmetric about y-axis hence it can't be EVEN
Graph is not symmetric about origin so it is ODD.
There is no breaking point in the graph so that means it is a Continuous function.
There is no hoirzontal or vertical or slant line which seems to be appearing to touch the graph at infinity so there is NO asymptote.
END behaviour means how y-changes when x approaches infinity.
From graph we can see that when x-approaches -∞ then y also approaches ∞.
when x-approaches +∞ then y also approaches +∞.
A) Plan A requires for a percentage increase of a number of students. This means that year after year the number of new students will increase. Plan B requires for a constant number of new students each year. This means that year after year the percentage increase would get smaller.
B) To solve this problem we will use formula for a growth of population:
Where:
final = final number of students
initial = initial number of students
percentage = requested percentage increase
t = number of years
We can insert numbers and solve for t:
For Plan B we can use simple formula
increase = 120
increase per year = 20
number of years = increase / (increase per year) = 120 / 20 = 6 years
Plan B is better to double the <span>enrollment.
C)We use same steps as in B) to solve this.
</span>
For Plan B we can use simple formula
increase = 240
increase per year = 20
number of years = increase / (increase per year) = 240 / 20 = 12 years
Plan A is better to triple the enrollment.
B) To solve this problem we will use formula for a growth of population:
Where:
final = final number of students
initial = initial number of students
percentage = requested percentage increase
t = number of years
We can insert numbers and solve for t:
For Plan B we can use simple formula
increase = 120
increase per year = 20
number of years = increase / (increase per year) = 120 / 20 = 6 years
Plan B is better to double the <span>enrollment.
C)We use same steps as in B) to solve this.
</span>
For Plan B we can use simple formula
increase = 240
increase per year = 20
number of years = increase / (increase per year) = 240 / 20 = 12 years
Plan A is better to triple the enrollment.