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Nikolay [14]
2 years ago
7

Jane is one of 50 students to take a standardized math test that includes 100 multiple choice questions. If she has the highest

score of any student with a raw score of 87, what is her percentile score?
Mathematics
1 answer:
Pepsi [2]2 years ago
8 0
Answer: 87%
Solution:
87 correct questions over 100 = 87/100 = .87 = (change to percent by moving the decimal 2 places to the right) 87%
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The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . The
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<em>Question:</em>

<em>Sal is trying to determine which cell phone and service plan to buy for his mother. The first phone costs $100 and $55 per month for unlimited usage. The second phone costs $150 and $51 per month for unlimited usage. </em>

<em>The inequality that will determine the number of months, x, that are required for the second phone to be less expensive is . </em>

<em>The solution to the inequality is . </em>

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Answer:

a. 150 + 51x < 100 + 55x

b. x > 12.5

c. At least 13 months

Step-by-step explanation:

Given

First Phone;

Cost = \$100

Additional = \$55 <em>(monthly)</em>

Second Phone;

Cost = \$150

<em />Additional = \$51<em> (monthly)</em>

<em></em>

Solving (a): The inequality

<em></em>

Represent the number of months with x

The first phone is expressed as:

100 + 55x

The second phone is expressed as:

150 + 51x

For the second to be less expensive that the first, the inequality is:

150 + 51x < 100 + 55x

Solving (b): Inequality Solution

150 + 51x < 100 + 55x

Collect Like Terms

51x-55x

-4x

Solve for x

x > -50/-4

x > 12.5

Solving (c): Interpret the solution in (b)

x > 12.5 implies 13, 14, 15....

Hence, She'll keep the second phone for a period of at least 13 months

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1 year ago
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Aleksandr-060686 [28]

Answer:

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we have

-3x-7

Solve for x

Adds 7 both sides

-3x

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Divide by -3 both sides

Remember that

When you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

so

x> 27/(-3)\\x>-9

The solution is the interval (-9,∞)

therefore

A number line goes from negative 10 to positive 10. An open circle appears at negative 9. The number line is shaded from negative 9 through positive 10.

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