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Firlakuza [10]
2 years ago
6

Harvey has “r” red peppers and one fourth as many orange peppers. Choose the expression that shows how many orange peppers Harve

y has A. 4/r B. r/1/4 C. r/4 D. 1/4/r
Mathematics
1 answer:
lana [24]2 years ago
4 0

Answer:

\frac{1}{4}r

Step-by-step explanation:

The amount of red pepper that Harvey has is r red peppers and one fourth as many orange peppers. What this means is that the number of orange pepper that Harvey has is one fourth the number of red peppers. Since the number of red pepper is r, therefore the number of orange pepper is given as:

Number of orange pepper = \frac{1}{4} \ of\ red\ pepper(r)

Number\ of\ orange\ pepper=\frac{1}{4}r

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Rob is making a scale model of the Solar System on the school field. He wants the distance from the Sun to Jupiter to be 8 metre
ANEK [815]

Answer:

1 : 9.75 * 10⁷

Step-by-step explanation:

To find n, we have to divide the real distance by the scale distance. This is 7.8 * 10⁸ / 8 = 0.975 * 10⁸ = 9.75 * 10⁷ which means that the ratio is 1 : 9.75 * 10⁷.

3 0
2 years ago
Complete the steps in solving the quadratic function 7x – 9 = 7x2 – 49x by completing the square. –9 = 7x2 – x –9 + = 7(x2 – 8x
anzhelika [568]

Answer:

A) 56 . . . . . . the (negative) sum of -7 and -49

b) 112 . . . . . the product of 7 and 16

c) 16 . . . . . . the square of 8/2

8 0
2 years ago
Read 2 more answers
A local hamburger shop sold a combined total of 768 hamburgers and cheeseburgers on Saturday. There were 68 more cheeseburgers s
almond37 [142]
There were 350 hamburgers sold on Saturday. Hope this helps!
3 0
2 years ago
Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

5 0
2 years ago
Jeri finds a pile of money with at least $\$200$. If she puts $\$50$ of the pile in her left pocket, gives away $\frac23$ of the
Marizza181 [45]

Answer:

The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350

Step-by-step explanation:

Here we have, pile of money ≥ $200

Amount in put the left pocket = $50

Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100

Amount put in right pocket = ≥ $150 - $100 ≥ $50

Total amount remaining with Jeri = $50 +≥ $50 ≥ $100

Also original pile - $200 < $100

Therefore where maximum amount given away to have more money = $200 we have

2/3× (original pile - 50) = $200

Maximum amount for original pile = $350

Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.

6 0
2 years ago
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