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Kamila [148]
2 years ago
9

3. If the measure of angle 4 is 6x + 20 and the meas-

Mathematics
1 answer:
Allushta [10]2 years ago
7 0

Answer:E

Step-by-step explanation:

If you add all the number together then you will get yourself to 120

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A recent survey by the American Automobile Association showed that a family of two adults and two children on vacation in the Un
masha68 [24]

Answer: We are given:

\mu=247,\sigma=60

We need to find the z scores for the following vacation expense amounts:

$197, $277, $310

We know that z score formula is:

z=\frac{x-\mu}{\sigma}

When x = 197, the z score is:

z=\frac{197-247}{60}

        =\frac{-50}{60}

        =-0.83

When x = 277, the z score is:

z=\frac{277-247}{60}

        =\frac{30}{60}

        =0.5

When x = 310, the z score is:

z=\frac{310-247}{60}

        =\frac{63}{60}

        =1.05

Therefore, the z scores for the vacation expense amounts $197 per day, $277 per day, and $310 per day are -0.83, 0.5 and 1.05 respectively


8 0
1 year ago
Read 2 more answers
The flagpole casts an 8 foot shadow as shown in the table at the same time the oak tree casts 12-foot shadow how tall is the oak
jolli1 [7]

How tall is the flagpole?

3 0
2 years ago
Ellen said she spent half her money for lunch and half of what was left for a movie. She now has $1.20. How much did she spend f
goldenfox [79]

Answer: She spend $1.20 for lunch.

Step-by-step explanation:

Let the total amount be 'x'.

Half of her money spend for lunch be \dfrac{x}{2}

Half of her money left for a movie be \dfrac{x}{2}

Amount she has now = $1.20

So, According to question, it becomes ,

\dfrac{x}{2}=1.20\\\\x=1.20\times 2\\\\x=\$2.40

Hence, Amount she spend for lunch is \dfrac{x}{2}=\dfrac{2.40}{2}=\$1.20

Therefore, she spend $1.20 for lunch.

8 0
1 year ago
Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The
abruzzese [7]

The question is incorrect.

The correct question is:

Three TAs are grading a final exam.

There are a total of 60 exams to grade.

(c) Suppose again that we are counting the ways to distribute exams to TAs and it matters which students' exams go to which TAs. The TAs grade at different rates, so the first TA will grade 25 exams, the second TA will grade 20 exams and the third TA will grade 15 exams. How many ways are there to distribute the exams?

Answer: 60!/(25!20!15!)

Step-by-step explanation:

The number of ways of arranging n unlike objects in a line is n! that is ‘n factorial’

n! = n × (n – 1) × (n – 2) ×…× 3 × 2 × 1

The number of ways of arranging n objects where p of one type are alike, q of a second type are alike, r of a third type are alike is given as:

n!/p! q! r!

Therefore,

The answer is 60!/25!20!15!

6 0
1 year ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
adoni [48]

Step-by-step explanation

<h3>Prerequisites:</h3>

<u>You need to know: </u>

b^2 - 4ac = 0 \Rightarrow 1 solution

b^2 - 4ac > 0 \Rightarrow 2 solutions

b^2 - 4ac < 0 \Rightarrow No\ real\ solutions

----------------------------------------------------------------

2x^2-7x-9 = 0

b^2 - 4ac

-7^2 - 4(2)(-9) = 121

2 Solutions

---------------------------------------------------------------

x^2-4x+4 = 0

b^2 - 4ac

-4^2 - 4(1)(4) = 0

1 Solution

---------------------------------------------------------------

4x^2-3x-1 = 0

b^2 - 4ac

-3^2 - 4(4)(-1) = 25

2 Solutions

---------------------------------------------------------------

x^2-2x-8 = 0

b^2 - 4ac

-2^2 - 4(1)(-8) = 36

2 Solutions

---------------------------------------------------------------

3x^2+5x+3 = 0

b^2 - 4ac

5^2 - 4(3)(3) = -11

No Solutions

---------------------------------------------------------------


3 0
2 years ago
Read 2 more answers
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